在WHERE子句中使用COUNT()

Question

我有以下SQL语句:

SELECT     C.LINKED_TABLE_ID AS CLIENT_DIWOR, I.STATUS AS AML_STATUS, dbo.CLIENT_MASTER.CLIENTCODE
FROM         AML_INFORMATION AS I INNER JOIN
                dbo.COMM_ENTRY AS C ON C.NAME_ID = I.CONTACT_ID AND C.TABLE_ID = 'C' AND C.PRIMARY_FLAG = 'Y' INNER JOIN
                dbo.CLIENT_MASTER ON C.LINKED_TABLE_ID = dbo.CLIENT_MASTER.DIWOR
WHERE I.CONTACT_ID = 234
    AND I.[STATUS] = 'CC'
    AND (CLIENT_MASTER.DIWOR = I.CONTACT_ID)
    AND (CLIENT_MASTER.POSTING_STATUS <> '')
    AND ((SELECT COUNT(CONTACT_ID) FROM AML_ID_DOCUMENT GROUP BY CONTACT_ID HAVING CONTACT_ID = 234) >1)

如果我运行它,它返回0记录,但是如果我删除最后一个AND语句,AND ((SELECT COUNT(CONTACT_ID) FROM AML_ID_DOCUMENT GROUP BY CONTACT_ID HAVING CONTACT_ID = 234) >1)它将返回我期望的记录.

是否可以这样使用COUNT()？顺便说一下,这个例子中的COUNT()返回2条记录,如果我把它包含在SELECT语句中,我也会得到0条记录.

谁能指出我正确的方向？

提前致谢.

Answer 1

你展示的剧本永远不应该返回任何东西......你的部分可以看起来像这样

   and (Select Count(*) from AML_ID_DOCUMENT  where CONTACT_ID =I.CONTACT_ID)>1

虽然它应该工作,因为它...

Answer 2

最后一部分不应该是这样的:

AND EXISTS (SELECT CONTACT_ID FROM AML_ID_DOCUMENT
      WHERE CONTACT_ID = 234
      GROUP BY CONTACT_ID
      HAVING COUNT(CONTACT_ID)>1)