MySQL GROUP BY"和过滤器"

Question

假设我有这样的查询:

SELECT name, GROUP_CONCAT(number)
FROM objects
GROUP BY name

它输出:

+----------+----------------------+
|  NAME    | GROUP_CONCAT(NUMBER) |
+----------+----------------------+
| false_1  | 2,1                  |
| false_2  | 3,4                  |
| true_1   | 4,3,2,1              |
| true_2   | 2,3                  |
+----------+----------------------+

现在我如何返回具有2 AND 3as的行number？

注意:此查询已分组 - 表有10行,如下所示:

+---------+--------+
|  NAME   | NUMBER |
+---------+--------+
| true_1  | 1      |
| true_1  | 2      |
| true_1  | 3      |
| ...     | ...    |
+---------+--------+

[链接到SQLFiddle]

Answer 1

SELECT name, GROUP_CONCAT(number)
FROM objects
WHERE number IN (2,3)
GROUP BY name
HAVING COUNT(*) = 2

• 参见SQLFiddle演示

或者如果要保留名称所具有的所有值,

SELECT  a.name, GROUP_CONCAT(A.number)
FROM    objects a
        INNER JOIN
        (
          SELECT name
          FROM objects
          WHERE number IN (2,3)
          GROUP BY name
          HAVING COUNT(*) = 2
        ) b ON a.Name = b.Name
GROUP BY a.name

• 参见SQLFiddle演示