如何在mysql存储过程中循环日期时间

Joy*_*Joy 3 mysql sql for-loop

即时通讯使用mysql存储过程,如何制作一个循环,每1小时变量strathour将有1小时间隔然后返回查询的总数.当starthour小于11月的日期时,它将具有1小时的间隔并执行查询.

这是我的代码:

DELIMITER $$

CREATE DEFINER=`root`@`%` PROCEDURE `sp_asessiontime`(
out `total` int
)
BEGIN

declare `starthour`, `endhour` datetime;
set `starthour` = '2012-09-20 01:59:00';
set `endhour` = '2012-09-20 02:00:00';


select count(terminalcount.terminalids) into total from (
select distinct ts.TerminalID `terminalids` from
tmptransactiondetails td
inner join transactionsummary ts
on td.TransactionSummaryID = ts.TransactionsSummaryID
where
td.ServiceID = 4
and
td.TransactionType in ('D','W')
and
(ts.DateStarted >= starthour and ts.DateStarted < endhour)
or
(ts.DateEnded >= starthour and ts.DateEnded < endhour)
or
(ts.DateStarted < starthour and starthour <= ts.DateEnded)
)as terminalcount;
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- 每1小时循环一次

while 

starthour < '2012-11-01 01:59:00' do
select starthour + interval 1 hour;
select total as totalnumber;

end while;

END
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十分感谢大家.

nun*_*cal 6

我不确定我的问题是否正确,但这是你在日期之间循环的方式

set currHour = '2012-09-20 01:59:00';
set endhour = '2012-09-21 02:00:00';

REPEAT

-- execute your queries for every hour

Set currHour = DATE_ADD(currHour,INTERVAL 1 HOUR);
UNTIL currHour > endhour END REPEAT;
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如果你必须使用while循环:

WHILE currHour < endhour DO
  -- execute your queries for every hour
  Set currHour = DATE_ADD(currHour,INTERVAL 1 HOUR);
END WHILE;
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