如何在matplotlib中制作自定义图例

Question

我目前用matplotlib以这种方式生成我的传奇:

if t==25:
    l1,l2 = ax2.plot(x320,vTemp320,'or',x320,vAnaTemp320,'-r')
elif t==50:
    l3,l4 = ax2.plot(x320,vTemp320,'ob',x320,vAnaTemp320,'-b')
else:
    l5,l6 = ax2.plot(x320,vTemp320,'og',x320,vAnaTemp320,'-g')
plt.legend((l1,l2,l3,l4,l5,l6), ('t=25 Simulation', 't=25 Analytical','t=50 Simulation', 't=50 Analytical','t=500 Simulation', 't=500 Analytical'),
   bbox_to_anchor=(-.25, 1), loc=2, borderaxespad=0.,prop={'size':12})

以某种方式工作看1.但我的传说中有重复的信息.

我宁愿分开传说.这样我就有了与时间t对应的不同颜色的线条.作为我的分析解决方案的正常线条是模拟结果的点.

这样的事情

- (红线)t = 25

- (蓝线)t = 50

- (绿线)t = 500

o Simulaton

- 分析解决方案

现在有人能用matplotlib实现这一目标吗？

Answer 1

您可以选择要在图例中显示的艺术家和标签,如下所示.您需要为图例中未实际绘制的元素创建自定义图稿.

import matplotlib.pyplot as plt
import numpy as np

x = np.linspace(0,10,31)

fig = plt.figure()
ax = fig.add_subplot(1,1,1)

#Plot analytic solution
ax.plot(x,1*x**2, color='r', label="t = 25")
ax.plot(x,2*x**2, color='b', label="t = 50")
ax.plot(x,3*x**2, color='g', label="t = 500")

#Plot simulation
ax.plot(x,1*x**2, color='r', linestyle='', marker='o')
ax.plot(x,2*x**2, color='b', linestyle='', marker='o')
ax.plot(x,3*x**2, color='g', linestyle='', marker='o')

#Get artists and labels for legend and chose which ones to display
handles, labels = ax.get_legend_handles_labels()
display = (0,1,2)

#Create custom artists
simArtist = plt.Line2D((0,1),(0,0), color='k', marker='o', linestyle='')
anyArtist = plt.Line2D((0,1),(0,0), color='k')

#Create legend from custom artist/label lists
ax.legend([handle for i,handle in enumerate(handles) if i in display]+[simArtist,anyArtist],
          [label for i,label in enumerate(labels) if i in display]+['Simulation', 'Analytic'])

plt.show()