Mac*_*iej 1792 t-sql sql-server sql-server-2008 sql-server-2012 sql-server-2016
如果不存在,我需要添加一个特定的列.我有类似以下内容,但它总是返回false:
IF EXISTS(SELECT *
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME = 'myTableName'
AND COLUMN_NAME = 'myColumnName')
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如何检查SQL Server数据库的表中是否存在列?
Mit*_*eat 1975
SQL Server 2005以后:
IF EXISTS(SELECT 1 FROM sys.columns
WHERE Name = N'columnName'
AND Object_ID = Object_ID(N'schemaName.tableName'))
BEGIN
-- Column Exists
END
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马丁史密斯的版本较短:
IF COL_LENGTH('schemaName.tableName', 'columnName') IS NOT NULL
BEGIN
-- Column Exists
END
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Mar*_*ith 964
更简洁的版本
IF COL_LENGTH('table_name','column_name') IS NULL
BEGIN
/* Column does not exist or caller does not have permission to view the object */
END
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关于查看元数据的权限的观点适用于所有答案,而不仅仅是这一点.
请注意,第一个参数表名称COL_LENGTH可以根据需要采用一个,两个或三个部分名称格式.
引用不同数据库中的表的示例是
COL_LENGTH('AdventureWorks2012.HumanResources.Department','ModifiedDate')
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与使用元数据视图相比,这个答案的一个不同之处在于元数据函数,例如COL_LENGTH始终只返回有关已提交更改的数据,而不管有效的隔离级别如何.
Luk*_*ett 142
调整以下内容以满足您的特定要求:
if not exists (select
column_name
from
INFORMATION_SCHEMA.columns
where
table_name = 'MyTable'
and column_name = 'MyColumn')
alter table MyTable add MyColumn int
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编辑以处理编辑问题:这应该工作 - 仔细查看代码中的愚蠢错误; 您是否在应用插入的同一数据库中查询INFORMATION_SCHEMA?在任何一个语句中,您的表/列名称中是否有拼写错误?
Leo*_*son 73
试试这个...
IF NOT EXISTS(
SELECT TOP 1 1
FROM INFORMATION_SCHEMA.COLUMNS
WHERE
[TABLE_NAME] = 'Employees'
AND [COLUMN_NAME] = 'EmployeeID')
BEGIN
ALTER TABLE [Employees]
ADD [EmployeeID] INT NULL
END
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Chr*_*ter 46
我更喜欢INFORMATION_SCHEMA.COLUMNS系统表,因为Microsoft不保证在版本之间保留系统表.例如,dbo.syscolumns仍然可以在SQL 2008中使用,但它已被弃用,并且可以在将来的任何时候删除.
小智 42
您可以使用信息架构系统视图来查找您感兴趣的表的几乎所有内容:
SELECT *
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME = 'yourTableName'
ORDER BY ORDINAL_POSITION
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您还可以使用Information_schema视图查询视图,存储过程以及有关数据库的任何内容.
Pரத*_*ீப் 41
对于正在检查列存在的人来说.
在SQL Server 2016中,您可以使用新的DIE语句而不是大IF包装器
ALTER TABLE Table_name DROP COLUMN IF EXISTS Column_name
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mdb*_*mdb 34
首先检查table/ column(id/ name)组合是否存在于dbo.syscolumns(包含字段定义的内部SQL Server表)中,如果没有,则发出相应的ALTER TABLE查询以添加它.例如:
IF NOT EXISTS ( SELECT *
FROM syscolumns
WHERE id = OBJECT_ID('Client')
AND name = 'Name' )
ALTER TABLE Client
ADD Name VARCHAR(64) NULL
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Mat*_*cey 32
尝试类似的东西:
CREATE FUNCTION ColumnExists(@TableName varchar(100), @ColumnName varchar(100))
RETURNS varchar(1) AS
BEGIN
DECLARE @Result varchar(1);
IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.Columns WHERE TABLE_NAME = @TableName AND COLUMN_NAME = @ColumnName)
BEGIN
SET @Result = 'T'
END
ELSE
BEGIN
SET @Result = 'F'
END
RETURN @Result;
END
GO
GRANT EXECUTE ON [ColumnExists] TO [whoever]
GO
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然后像这样使用它:
IF ColumnExists('xxx', 'yyyy') = 'F'
BEGIN
ALTER TABLE xxx
ADD yyyyy varChar(10) NOT NULL
END
GO
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它应该适用于SQL Server 2000和SQL Server 2005.不确定SQL Server 2008,但不明白为什么不.
bra*_*uar 28
我的一位好朋友和同事向我展示了如何使用IFSQL函数块OBJECT_ID和COLUMNPROPERTYSQL SERVER 2005+来检查列.您可以使用类似于以下内容的内容:
IF (OBJECT_ID(N'[dbo].[myTable]') IS NOT NULL AND
COLUMNPROPERTY( OBJECT_ID(N'[dbo].[myTable]'), 'ThisColumnDoesNotExist', 'ColumnId') IS NULL)
BEGIN
SELECT 'Column does not exist -- You can add TSQL to add the column here'
END
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小智 25
declare @myColumn as nvarchar(128)
set @myColumn = 'myColumn'
if not exists (
select 1
from information_schema.columns columns
where columns.table_catalog = 'myDatabase'
and columns.table_schema = 'mySchema'
and columns.table_name = 'myTable'
and columns.column_name = @myColumn
)
begin
exec('alter table myDatabase.mySchema.myTable add'
+' ['+@myColumn+'] bigint null')
end
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Joe*_*e M 21
这在SQL 2000中对我有用:
IF EXISTS
(
SELECT *
FROM INFORMATION_SCHEMA.COLUMNS
WHERE table_name = 'table_name'
AND column_name = 'column_name'
)
BEGIN
...
END
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小智 21
试试这个
SELECT COLUMNS.*
FROM INFORMATION_SCHEMA.COLUMNS COLUMNS,
INFORMATION_SCHEMA.TABLES TABLES
WHERE COLUMNS.TABLE_NAME = TABLES.TABLE_NAME
AND Upper(COLUMNS.COLUMN_NAME) = Upper('column_name')
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Fro*_*III 18
我需要类似于SQL SERVER 2000,正如@Mitch指出的那样,这只适用于2005+.
它应该对其他人有帮助吗,这最终对我有用:
if exists (
select *
from
sysobjects, syscolumns
where
sysobjects.id = syscolumns.id
and sysobjects.name = 'table'
and syscolumns.name = 'column')
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小智 15
if exists (
select *
from INFORMATION_SCHEMA.COLUMNS
where TABLE_NAME = '<table_name>'
and COLUMN_NAME = '<column_name>'
) begin
print 'Column you have specified exists'
end else begin
print 'Column does not exist'
end
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Na3*_*30m 12
IF NOT EXISTS( SELECT NULL
FROM INFORMATION_SCHEMA.COLUMNS
WHERE table_name = 'TableName'
AND table_schema = 'SchemaName'
AND column_name = 'ColumnName') BEGIN
ALTER TABLE [SchemaName].[TableName] ADD [ColumnName] int(1) NOT NULL default '0';
END;
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Nis*_*had 10
select distinct object_name(sc.id)
from syscolumns sc,sysobjects so
where sc.name like '%col_name%' and so.type='U'
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cro*_*sek 10
接受答案的临时表版本:
if (exists(select 1
from tempdb.sys.columns
where Name = 'columnName'
and Object_ID = object_id('tempdb..#tableName')))
begin
...
end
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Wheat的答案很好,但假设您在任何架构或数据库中没有任何相同的表名/列名对.为了使其安全,请使用此...
select *
from Information_Schema.Columns
where Table_Catalog = 'DatabaseName'
and Table_Schema = 'SchemaName'
and Table_Name = 'TableName'
and Column_Name = 'ColumnName'
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小智 7
有几种方法可以检查列的存在.我强烈建议使用INFORMATION_SCHEMA.COLUMNS它,因为它是为了与用户沟通而创建的.考虑以下表格:
sys.objects
sys.columns
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甚至可以检查一些其他访问方法 system catalog.
此外,无需使用SELECT *,只需通过测试NULL value
IF EXISTS(
SELECT NULL
FROM INFORMATION_SCHEMA.COLUMNS
WHERE
TABLE_NAME = 'myTableName'
AND COLUMN_NAME = 'myColumnName'
)
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小智 7
另一个贡献是以下示例,如果该列不存在,则添加该列。
USE [Northwind]
GO
IF NOT EXISTS(SELECT * FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME = 'Categories'
AND COLUMN_NAME = 'Note')
BEGIN
ALTER TABLE Categories ADD Note NVARCHAR(800) NULL
END
GO
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这是我用来管理数据库中列添加的简单脚本:
IF NOT EXISTS (
SELECT *
FROM sys.Columns
WHERE Name = N'QbId'
AND Object_Id = Object_Id(N'Driver')
)
BEGIN
ALTER TABLE Driver ADD QbId NVARCHAR(20) NULL
END
ELSE
BEGIN
PRINT 'QbId is already added on Driver'
END
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在此示例中,Name是ColumnName要添加的和Object_Id是TableName
最简单易懂的解决方案之一是:
IF COL_LENGTH('Table_Name','Column_Name') IS NULL
BEGIN
-- Column Not Exists, implement your logic
END
ELSE
BEGIN
-- Column Exists, implement your logic
END
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如果列不存在,请执行以下操作:
BEGIN
IF (COL_LENGTH('[dbo].[Table]', 'Column ') IS NULL)
BEGIN
//Do something
END
END;
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如果列存在,请执行某些操作:
BEGIN
IF (COL_LENGTH('[dbo].[Table]', 'Column ') IS NOT NULL)
BEGIN
//Do something
END
END;
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