Joh*_*len 0 python dictionary
如果我有d = {"key": (5,4,"val1","val2",2)},我如何从元组中获取val1并将其自身转换为列表?
d = {"key": (5,4,"val1","val2",2)}
mgi*_*son 6
[d['key'][2]] 应该做的诀窍......
[d['key'][2]]
打破它:
d['key']
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