Edu*_*pat 57 inheritance constructor extends superclass dart
如何在Dart中调用超级构造函数?是否可以调用命名的超级构造函数?
Edu*_*pat 75
是的,语法接近C#,这是一个默认构造函数和命名构造函数的示例:
class Foo {
Foo(int a, int b) {
//Code of constructor
}
Foo.named(int c, int d) {
//Code of named constructor
}
}
class Bar extends Foo {
Bar(int a, int b) : super(a, b);
}
class Baz extends Foo {
Baz(int c, int d) : super.named(c, d);
}
Run Code Online (Sandbox Code Playgroud)
Sob*_*had 22
这是我与您共享的文件,按原样运行。您将学习如何调用超级构造函数,以及如何调用超级参数化构造函数。
/ Objectives
// 1. Inheritance with Default Constructor and Parameterised Constructor
// 2. Inheritance with Named Constructor
void main() {
var dog1 = Dog("Labrador", "Black");
print("");
var dog2 = Dog("Pug", "Brown");
print("");
var dog3 = Dog.myNamedConstructor("German Shepherd", "Black-Brown");
}
class Animal {
String color;
Animal(String color) {
this.color = color;
print("Animal class constructor");
}
Animal.myAnimalNamedConstrctor(String color) {
print("Animal class named constructor");
}
}
class Dog extends Animal {
String breed;
Dog(String breed, String color) : super(color) {
this.breed = breed;
print("Dog class constructor");
}
Dog.myNamedConstructor(String breed, String color) : super.myAnimalNamedConstrctor(color) {
this.breed = breed;
print("Dog class Named Constructor");
}
}
Run Code Online (Sandbox Code Playgroud)
小智 7
带有可选参数的构造函数的情况
class Foo {
String a;
int b;
Foo({this.a, this.b});
}
class Bar extends Foo {
Bar({a,b}) : super(a:a, b:b);
}
Run Code Online (Sandbox Code Playgroud)
是的,但仅当您创建的超类和子类位于同一个库中时.(由于私有标识符在整个库中可见,因此它们被定义).私有标识符是以下划线开头的标识符.
class Foo {
Foo._private(int a, int b) {
//Code of private named constructor
}
}
class Bar extends Foo {
Bar(int a, int b) : super._private(a,b);
}
Run Code Online (Sandbox Code Playgroud)