我有一个名为的主类theGarage,它包含我们的客户,供应商和工作类的实例.
我想将程序数据保存到XML文件,我使用了下面的代码(只是一个片段,我有其他类的匹配代码).我想知道是否有一种更简单的方法来执行此操作,例如将整个theGarage类写入XML文件并将其读入,而不必像下面那样编写所有这些代码.
public void saveToFile()
{
using (XmlWriter writer = XmlWriter.Create("theGarage.xml"))
{
writer.WriteStartDocument();
///
writer.WriteStartElement("theGarage");
writer.WriteStartElement("Customers");
foreach (Customer Customer in Program.theGarage.Customers)
{
writer.WriteStartElement("Customer");
writer.WriteElementString("FirstName", Customer.FirstName);
writer.WriteElementString("LastName", Customer.LastName);
writer.WriteElementString("Address1", Customer.Address1);
writer.WriteElementString("Address2", Customer.Address2);
writer.WriteElementString("Town", Customer.Town);
writer.WriteElementString("County", Customer.County);
writer.WriteElementString("PostCode", Customer.Postcode);
writer.WriteElementString("TelephoneHome", Customer.TelephoneHome);
writer.WriteElementString("TelephoneMob", Customer.TelephoneMob);
//begin vehicle list
writer.WriteStartElement("Vehicles");
foreach (Vehicle Vehicle in Customer.Cars)
{
writer.WriteStartElement("Vehicle");
writer.WriteElementString("Make", Vehicle.Make);
writer.WriteElementString("Model", Vehicle.Model);
writer.WriteElementString("Colour", Vehicle.Colour);
writer.WriteElementString("EngineSize", Vehicle.EngineSize);
writer.WriteElementString("Registration", Vehicle.Registration);
writer.WriteElementString("Year", Vehicle.YearOfFirstReg);
writer.WriteEndElement();
}
writer.WriteEndElement();
writer.WriteEndElement();
}
}
}
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Mic*_*uda 44
有更简单的序列化对象的方法,XmlSerializer而不是使用.见文档这里.
将车库序列化为文件的代码片段可能如下所示:
var garage = new theGarage();
// TODO init your garage..
XmlSerializer xs = new XmlSerializer(typeof(theGarage));
TextWriter tw = new StreamWriter(@"c:\temp\garage.xml");
xs.Serialize(tw, garage);
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和从文件加载车库的代码:
using(var sr = new StreamReader(@"c:\temp\garage.xml"))
{
garage = (theGarage)xs.Deserialize(sr);
}
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那么一些漂亮的扩展方法呢,那么你可以轻松地读/写这个文件.
public static class Extensions
{
public static string ToXml(this object obj)
{
XmlSerializer s = new XmlSerializer(obj.GetType());
using (StringWriter writer = new StringWriter())
{
s.Serialize(writer, obj);
return writer.ToString();
}
}
public static T FromXml<T>(this string data)
{
XmlSerializer s = new XmlSerializer(typeof(T));
using (StringReader reader = new StringReader(data))
{
object obj = s.Deserialize(reader);
return (T)obj;
}
}
}
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例
var xmlData = myObject.ToXml();
var anotherObject = xmlData.FromXml<ObjectType>();
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