我经历了很多谷歌搜索,我发现很多例子都不适用于我.这是一个简单的问题,我觉得有一个简单的答案,没有定义新的类\ modules等...
我的代码是这样的:
Console.WriteLine ("Please enter an IP address or hostname");
string host = Console.ReadLine ();
***IP = resolved "host"***
Socket s = new Socket (AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.IP);
s.Connect (IP, 80);
s.close();
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我如何实际解析IP变量?
Kol*_*lja 76
您只需使用DNS类即可:
IPHostEntry hostEntry;
hostEntry= Dns.GetHostEntry(host);
//you might get more than one ip for a hostname since
//DNS supports more than one record
if (hostEntry.AddressList.Length > 0)
{
var ip = hostEntry.AddressList[0];
Socket s = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.IP);
s.Connect(ip, 80);
}
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par*_*agy 30
string howtogeek = "www.howtogeek.com";
IPAddress[] addresslist = Dns.GetHostAddresses(howtogeek);
foreach (IPAddress theaddress in addresslist)
{
Console.WriteLine(theaddress.ToString());
}
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请注意,接受的答案可以解析为 IPv6。我试图连接到不接受 IPv6 作为输入字符串的服务。
因此,如果您想获得 IPv4,请尝试使用此代码段:
using System.Linq;
string host = "google.com";
Dns.GetHostEntry(host).AddressList.First(addr => addr.AddressFamily == System.Net.Sockets.AddressFamily.InterNetwork)
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