具有@OneToOne关系的jpa规范

Shi*_*ami 3 java repository criteria-api jpa-2.0

我想将jpa信息库与规范一起使用

现在我有两张桌子

@Entity
@Table(name="user")
public class User implements Serializable {

private static final long serialVersionUID = 1L;

private Long idUser;

private Area area;

@Id @GeneratedValue(strategy=GenerationType.AUTO)
@Column(name="iduser")
public Long getIdUser() {
return idUser;
}
public void setIdUser(Long idUser) {
this.idUser = idUser;
}

@OneToOne(fetch=FetchType.LAZY)
@JoinColumn(name="idarea")
public Area getArea() {
    return area;
}

public void setArea(Area area) {
    this.area = area;
}

}
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和面积表

@Entity
@Table(name = "area")
public class Area {

@Id @GeneratedValue(strategy=GenerationType.AUTO)
@Column(name="idarea")
private Long idArea;

@Column(name="area_name")
private String areaName;

public Long getIdArea() {
    return idArea;
}

public void setIdArea(Long idArea) {
    this.idArea = idArea;
}

public String getAreaName() {
    return areaName;
}

public void setAreaName(String areaName) {
    this.areaName = areaName;
}

}
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然后,我的用户存储库还扩展了JpaSpecificationExecutor

public interface UserRepository extends   CrudRepository<User,Long>,JpaSpecificationExecutor<User> {
}
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最后我有一个简单的规范

public class UserSpecification {

public static Specification<User> findByAreaName(final String areaName){
    return new Specification<User>() {

        @Override
        public Predicate toPredicate(Root<User> root,
                CriteriaQuery<?> criteria, CriteriaBuilder cb) {
            return cb.equal(root.<String>get("??????"),areaName);
        }
    };

}

}
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所以,我的问题是:我必须在“ ?????”中输入什么?这是表区域的areaName吗?

Chr*_*ian 5

你可以试试

return cb.equal((Path<String>) ((Path<Area>) root.get("area")).get("areaName"),areaName);
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而且您必须确保Area被加载,因为它是惰性的。

编辑:正如我在评论中提到的那样,也许只是尝试不进行任何投射。

对于这种情况,我提供了一种方法,您可以根据需要进行调整:

@SuppressWarnings("unchecked")
private <T, R> Path<R> getPath(Class<R> resultType, Path<T> root, String path) {
    String[] pathElements = path.split("\\.");
    Path<?> retVal = root;
    for (String pathEl : pathElements) {
        retVal = (Path<R>) retVal.get(pathEl);
    }
    return (Path<R>) retVal;
}
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它以点符号进行调用以获取路径。您的情况是:

getPath(String.class, root, "area.areaName");
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希望能帮助到你!