Ric*_*Sch 5 c++ error-handling integer infinite-loop
我遇到了一个非常简单的代码问题.我想接受1到3之间的整数,并进行错误检查.它适用于检查太大或太小的数字,但是当输入字母/数字组合时,它会陷入无限循环.建议?
#include <iostream>
using namespace std;
int main(int argc, char *argv[]){
int input;
cout << "\nPlease enter a number from 1 to 3:" << endl;
cout << "-> ";
cin >> input;
while(input< 1 || input> 3){
cout << "\n---------------------------------------" << endl;
cout << "\n[!] The number you entered was invalid." << endl;
cout << "\nPlease re-enter a number from 1 to 3" << endl;
cout << "-> ";
cin >> input;
}
cout << "You chose " << input << endl;
}
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问题是:
cin >> input;
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当您尝试读取非数字值时,将导致设置坏位.在那之后,任何使用它的尝试都会operator>>被忽略.
因此,纠正此问题的方法是测试流是否处于良好状态,如果不是,则重置状态标志并再次尝试读取.但请注意,输入错误(导致问题)仍然在输入上,因此您需要确保将其丢弃.
if (cin >> input)
{
// It worked (input is now in a good state)
}
else
{
// input is in a bad state.
// So first clear the state.
cin.clear();
// Now you must get rid of the bad input.
// Personally I would just ignore the rest of the line
cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
// now that you have reset the stream you can go back and try and read again.
}
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为了防止它被卡住(这是由设置的坏位引起)读入字符串然后使用字符串流来解析用户输入.我也更喜欢这种方法(用于用户交互式输入),因为它允许更容易地组合不同类型的阅读(即组合operator>>,std::getline()因为你可以在字符串流上使用它们).
#include <iostream>
#include <sstream>
#include <string>
// using namespace std;
// Try to stop using this.
// For anything other than a toy program it becomes a problem.
int main(int argc, char *argv[])
{
int input;
std::string line;
while(std::getline(std::cin, line)) // read a line at a time for parsing.
{
std::stringstream linestream(line);
if (!(linestream >> input))
{
// input was not a number
// Error message and try again
continue;
}
if ((input < 1) || (input > 3))
{
// Error out of range
// Message and try again
continue;
}
char errorTest;
if (linestream >> errorTest)
{
// There was extra stuff on the same line.
// ie sobody typed 2x<enter>
// Error Message;
continue;
}
// it worked perfectly.
// The value is now in input.
// So break out of the loop.
break;
}
}
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