只获取新的电子邮件imaplib和python

Question

这是较大项目的一小部分.我只需要获取未读电子邮件并解析其标题.如何修改以下脚本以仅获取未读电子邮件？

conn = imaplib.IMAP4_SSL(imap_server)
conn.login(imap_user, imap_password)

status, messages = conn.select('INBOX')    

if status != "OK":
    print "Incorrect mail box"
    exit()

print messages

Answer 1

像这样的东西可以解决问题.

conn = imaplib.IMAP4_SSL(imap_server)

try:
    (retcode, capabilities) = conn.login(imap_user, imap_password)
except:
    print sys.exc_info()[1]
    sys.exit(1)

conn.select(readonly=1) # Select inbox or default namespace
(retcode, messages) = conn.search(None, '(UNSEEN)')
if retcode == 'OK':
    for num in messages[0].split(' '):
        print 'Processing :', message
        typ, data = conn.fetch(num,'(RFC822)')
        msg = email.message_from_string(data[0][1])
        typ, data = conn.store(num,'-FLAGS','\\Seen')
        if ret == 'OK':
            print data,'\n',30*'-'
            print msg

conn.close()

这里还有一个重复的问题 - 自从我上次检查python imaplib2以来,发现添加到imap邮箱的新消息？

两个有用的功能供您检索的身体,你检测到新邮件的附件(参考:？如何使用Python中imaplib获取电子邮件正文) -

def getMsgs(servername="myimapserverfqdn"):
  usernm = getpass.getuser()
  passwd = getpass.getpass()
  subject = 'Your SSL Certificate'
  conn = imaplib.IMAP4_SSL(servername)
  conn.login(usernm,passwd)
  conn.select('Inbox')
  typ, data = conn.search(None,'(UNSEEN SUBJECT "%s")' % subject)
  for num in data[0].split():
    typ, data = conn.fetch(num,'(RFC822)')
    msg = email.message_from_string(data[0][1])
    typ, data = conn.store(num,'-FLAGS','\\Seen')
    yield msg

def getAttachment(msg,check):
  for part in msg.walk():
    if part.get_content_type() == 'application/octet-stream':
      if check(part.get_filename()):
        return part.get_payload(decode=1)

Answer 2

上面的答案实际上不再起作用或者从来没有做过但我修改它所以它只返回看不见的消息,它曾经给出:错误无法解析fetch命令或类似的东西这里是一个工作代码:

mail = imaplib.IMAP4_SSL('imap.gmail.com')
(retcode, capabilities) = mail.login('email','pass')
mail.list()
mail.select('inbox')

n=0
(retcode, messages) = mail.search(None, '(UNSEEN)')
if retcode == 'OK':

   for num in messages[0].split() :
      print 'Processing '
      n=n+1
      typ, data = mail.fetch(num,'(RFC822)')
      for response_part in data:
         if isinstance(response_part, tuple):
             original = email.message_from_string(response_part[1])

             print original['From']
             print original['Subject']
             typ, data = mail.store(num,'+FLAGS','\\Seen')

print n

我认为错误来自于,messages[0].split(' ')但上述代码应该可以正常工作.

还要注意,+FLAGS而不是-FLAGS将消息标记为已读.

Answer 3

original = email.message_from_string(response_part[1])

需要更改为：

original = email.message_from_bytes(response_part[1])

Answer 4

您可以使用 imap_tools 包：https ://pypi.org/project/imap-tools/

from imap_tools import MailBox, AND
with MailBox('imap.mail.com').login('test@mail.com', 'password', 'INBOX') as mailbox:
    # get unseen emails from INBOX folder
    for msg in mailbox.fetch(AND(seen=False)):
        print(msg.date, len(msg.html or msg.text))