如何使用span设置PHP echo输出的样式

Question

我正在尝试设置每个回声的输出.

理想情况下,我想<span class=""> </span>用于每个回声,但我不太清楚如何实现这一目标.

$result = mysql_query("SELECT * FROM Blog");
while($row = mysql_fetch_array($result))
{
    echo $row['Date'];
    echo $row['Title'];
    echo $row['Message'];
    echo "<img src='".$row['Image']."'/>";
}

mysql_close($con);

Answer 1

$result = mysql_query("SELECT * FROM Blog");
while($row = mysql_fetch_array($result))
    {
    echo "<span class=\"myclass\">$row['Date']</span>";
    echo "<span class=\"myclass\">$row['Title']</span>";
    echo "<span class=\"myclass\">$row['Message']</span>";
    echo "<img src='".$row['Image']."'/>";
    }

mysql_close($con);

或者,更好,在表中:

$result = mysql_query("SELECT * FROM Blog");
echo "<table>"
while($row = mysql_fetch_array($result))  {
    echo "<tr>"
    echo "<td>$row['Date']</td>";
    echo "<td>$row['Title']</td>";
    echo "<td>$row['Message']</td>";
    echo "<td><img src='".$row['Image']."'/></td>";
    echo "</tr>"
}
echo "</table>"

mysql_close($con);

然后,您可以使用类为每个行和列设置样式.