将2d数组char传递给函数

Question

我正在尝试将带有字符串的2D数组传递给函数.我在令牌之前一直得到预期的表达式.

这段代码的重点是阅读wordsearch拼图,然后找到拼图中的单词.我将编写一个函数用于前向搜索,后向搜索,然后上下搜索.

我该如何摆脱这个错误？错误在我称之为前向功能的最底部.

    /*Andrea Hatfield CPE 101 October 31st, 2012*/
    #include <stdio.h>
    #include <string.h>

    int forward(char words[][8], char puzzle[][11]);


    int main()
    {
    char puzzle[11][11];
    char words[8][8];
    FILE *fin, *fwords;
    int i = 0;
    int j= 0;

    fin = fopen("puzzle.in", "r"); 
    fwords = fopen("words.in", "r");


    if(fin == NULL) /*Reads in the puzzle file*/
    printf("File does not exist");
    else
    {
            while(fscanf(fin,"%s", puzzle[i])!=EOF)
            {
                    printf("%s\n", puzzle[i]);
                    i++;
            }


    }

    if(fwords == NULL) /*Reads in the words the puzzle will search for */
    printf("File does not exist");
    else
    {
            while(fscanf(fwords, "%s", words[j])!=EOF)
            {
                    printf("%s\n", words[j]);
            }
    }


    forward(&words[][8], &puzzle[][11]); /*Error at this point*/
    return(0);
    }

Answer 1

得到你想要的东西有点难,但这里有一个问题:

forward(&words[][8], &puzzle[][11]);

试试这个:

forward(words, puzzle);

以下是另外两个应该从这里提到的选项:

#define ROWS 4
#define COLS 5

void func(int array[ROWS][COLS]) {
  int i, j;

  for (i=0; i<ROWS; i++) {
    for (j=0; j<COLS; j++) {
      array[i][j] = i*j;
    }
  }
}

void func_vla(int rows, int cols, int array[rows][cols]) {
  int i, j;

  for (i=0; i<rows; i++) {
    for (j=0; j<cols; j++) {
      array[i][j] = i*j;
    }
  }
}

int main() {
  int x[ROWS][COLS];

  func(x);
  func_vla(ROWS, COLS, x);
}