如何解决将表达式转换为数据类型int的算术溢出错误?

Ang*_*ker 5 sql sql-server sql-server-2005

我有以下查询:

-- CTE to remove outliers, e.g. remove the fastest and slowest results
;WITH MinMaxCTE AS 
(
  SELECT ServerName, CONVERT(VARCHAR(10), UpdatedOn, 101) AS [Date], Version, 
    MIN(JaguarStartupTime) AS MinStartTime, MAX(JaguarStartupTime) AS MaxStartTime
  FROM dbo.MachineConfiguration (NOLOCK)
  WHERE DomainLogin NOT IN (SELECT DomainLogin FROM dbo.SupportGroup)
  GROUP BY ServerName, CONVERT(VARCHAR(10), UpdatedOn, 101), Version
)

SELECT  AVG(mc.JaguarStartupTime) AS AverageTime
    , COUNT(*) AS NumEntries
    , mc.Version
FROM    #Eligible mc (NOLOCK)
JOIN MinMaxCTE cte ON mc.ServerName = cte.ServerName 
  AND CONVERT(VARCHAR(10), mc.UpdatedOn, 101) = cte.[Date] 
  AND mc.Version = cte.Version 
  AND mc.JaguarStartupTime <> cte.MinStartTime 
  AND mc.JaguarStartupTime <> cte.MaxStartTime
GROUP BY mc.Version
ORDER BY Version DESC, AVG(mc.JaguarStartupTime) ASC
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#Eligible临时表的定义是

create table #Eligible (
    Version nvarchar(50), JaguarStartupTime int, 
    ServerName nvarchar(50), UpdatedOn datetime )
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无论我注释掉什么条件或聚合,我总是得到以下错误:Arithmetic overflow error converting expression to data type int.

我在哪里可以离开?我该如何进一步调试?

编辑:示例数据

Version JaguarStartupTime    ServerName     UpdatedOn
6.4.6.082      16040         NewOrleansLA   2012-08-08 12:34:12.330
6.5.1.012      40390         BatonRougeLA   2012-08-08 18:33:17.440
6.5.1.012      48379         HonoluluHI     2012-08-09 04:42:50.453
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Ric*_*ews 5

你有没有尝试过将你的jaguarstartup时间投射到你的平均聚合中的bigint ...

AVG(CAST(mc.JaguarStartupTime AS BIGINT))

这应该解决算术溢出.

要计算平均值,服务器需要首先对所有的int进行求和,因此平均所需的数据类型需要能够存储这些值的总和,即使返回的答案在int的范围内也是如此.