如何在C++中将两个元组作为参数发送

Question

您好我是C++的新手,我试图创建一个带有两个复数的程序,对它们进行优化并返回总和.

我打算做的是将两个元组发送到一个函数并返回一个元组.

typedef tuple<float, float> complex_tuple;
  complex_tuple a_tuple(a, b);
  complex_tuple b_tuple(c, d);


    cout << sum(a_tuple, b_tuple);

这是我的功能:

tuple<float,float> sum(tuple<float, float>a, tuple<float, float>b){
  float a_real= get<0>(a);
  float a_imag= get<1>(a);
  float b_real= get<0>(b);
  float b_imag= get<1>(b);
  return tuple<float, float>(a_real+b_real, a_imag+b_imag);
}

我得到的错误是:

0.cc:28:31: Error: no match for "operator<<" in "std::cout << sum(std::tuple<float, float>, std::tuple<float, float>)(b_tuple)"

我究竟做错了什么？

Answer 1

您试图说要打印总和cout,但cout不知道如何处理类型的值complex_tuple.

提供重载operator<<(ostream&, const complex_tuple&)以允许代码编译:

ostream& operator<<(ostream& os, const complex_tuple& tuple) {
    os << get<0>(tuple) << "+" << get<1>(tuple) << "i";
    return os;
}

更多信息.