UIAlertview代码上的EXC_BAD_ACCESS = 1

Question

我在[alert show]行上获得了EXC_BAD_ACCESS.

为什么我得到这个？

 alert = [[UIAlertView alloc]initWithTitle:@"Application Alert" message:@"all date popup" delegate:self cancelButtonTitle:nil otherButtonTitles:@"Update",nil];

 [alert show]; //EXC_BAD_ACCESS on this line

Answer 1

此崩溃必须在iOS 6上.此崩溃的解决方案如下:

[alert performSelectorOnMainThread:@selector(show) withObject:nil waitUntilDone:YES];

Answer 2

只需要委托nil,不要将自己委托给代理.如下所示

alert = [[UIAlertView alloc]initWithTitle:@"Application Alert" message:@"all date popup" delegate:nil cancelButtonTitle:nil otherButtonTitles:@"Update",nil];

[alert show];

如果你在委托中使用self,那么你将不得不使用alert delegate方法

- (void)alertView:(UIAlertView *)alertView clickedButtonAtIndex:(NSInteger)buttonIndex

然后它不会给EXC_Bad_Excess.let我知道它是否有效.. !!!!快乐编码....