如何在Heroku上使用JAX-RS找出传入的RESTful请求的IP?

Luk*_*uke 30 rest jax-rs heroku jersey grizzly

我正在基于一个示例编写一个托管在Heroku上的Java RESTful服务 - > https://api.heroku.com/myapps/template-java-jaxrs/clone

我的样品服务是:

package com.example.services;

import com.example.models.Time;

import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;

@Path("/time")
@Produces(MediaType.APPLICATION_JSON)
public class TimeService {

    @GET
    public Time get() {
        return new Time();
    }

}
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我的主要是:

public class Main {

    public static final String BASE_URI = getBaseURI();

    /**
     * @param args
     */
    public static void main(String[] args) throws Exception{
        final Map<String, String> initParams = new HashMap<String, String>();
        initParams.put("com.sun.jersey.config.property.packages","services.contracts"); 

        System.out.println("Starting grizzly...");
        SelectorThread threadSelector = GrizzlyWebContainerFactory.create(BASE_URI, initParams);
        System.out.println(String.format("Jersey started with WADL available at %sapplication.wadl.",BASE_URI, BASE_URI));
    }

    private static String getBaseURI() 
    {
        return "http://localhost:"+(System.getenv("PORT")!=null?System.getenv("PORT"):"9998")+"/";      
    }

}
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我的问题是如何在我的服务中找到请求来自的IP地址和端口组合?我已经阅读了@Context上的内容,它注入了javax.ws.rs.core.HttpHeaders,javax.ws.rs.core.Request等.但是,没有传入的IP或端口信息.

我知道如果你实现com.sun.grizzly.tcp.Adapter,你可以这样做:

public static void main(String[] args) {
    SelectorThread st = new SelectorThread();
    st.setPort(8282);
    st.setAdapter(new EmbeddedServer());
    try {
        st.initEndpoint();
        st.startEndpoint();
    } catch (Exception e) {
        System.out.println("Exception in SelectorThread: " + e);
    } finally {
        if (st.isRunning()) {
            st.stopEndpoint();
        }
    }
}

public void service(Request request, Response response)
        throws Exception {
    String requestURI = request.requestURI().toString();

    System.out.println("New incoming request with URI: " + requestURI);
    System.out.println("Request Method is: " + request.method());

    if (request.method().toString().equalsIgnoreCase("GET")) {
        response.setStatus(HttpURLConnection.HTTP_OK);
        byte[] bytes = "Here is my response text".getBytes();

        ByteChunk chunk = new ByteChunk();
        response.setContentLength(bytes.length);
        response.setContentType("text/plain");
        chunk.append(bytes, 0, bytes.length);
        OutputBuffer buffer = response.getOutputBuffer();
        buffer.doWrite(chunk, response);
        response.finish();
    }
}

public void afterService(Request request, Response response)
        throws Exception {
    request.recycle();
    response.recycle();
}
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和访问

    request.remoteAddr()
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但我真的想以更加结构化的方式分离我的RESTful API,就像我的第一个实现一样.

任何帮助将不胜感激.谢谢!

小智 52

你可以注入HttpServletRequest:

@GET
@Produces(MediaType.TEXT_PLAIN)
public Response getIp(@Context HttpServletRequest req) {
    String remoteHost = req.getRemoteHost();
    String remoteAddr = req.getRemoteAddr();
    int remotePort = req.getRemotePort();
    String msg = remoteHost + " (" + remoteAddr + ":" + remotePort + ")";
    return Response.ok(msg).build();
}
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  • 我想通了,你必须从Http Header中提取`X-Forwarded-For`标题. (10认同)
  • 只是想提到任何人来到这里使用JAX-RS进行maven配置,以解决原始海报问题中所述的问题.你必须在`pom.xml`(http://mvnrepository.com/artifact/javax.servlet/servlet-api/2.5)中包含`servlet-api`的`javax-servlet`然后`import javax. servlet.http.HttpServletRequest`.`Context`类已经在JAX-RS中:`import javax.ws.rs.core.Context`. (4认同)
  • 我查了一个主机名,而req.getRemoteHost()确实是一个私有IP`ip-10-42-223-182.ec2.internal`,它似乎是一个EC2 IP. (2认同)

Eth*_*han 11

正如Luke所说,在使用Heroku时,远程主机是AWS应用层,因此是EC2 IP地址.

"X-Forwarded-For"标题就是答案:

String ip = "0.0.0.0";
try {
    ip = req.getHeader("X-Forwarded-For").split(",")[0];
} catch (Exception ignored){}
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bol*_*y38 6

基于@ user647772和@Ethan fusion.谢谢他们;)

注入HttpServletRequest:

@GET
@Produces(MediaType.TEXT_PLAIN)
public Response getFromp(@Context HttpServletRequest req) {
    String from = _getUserFrom(req);
    return Response.ok(from).build();
}

private String _getUserFrom(HttpServletRequest req) {
    String xForwardedFor = req.getHeader("X-Forwarded-For");
    xForwardedFor = xForwardedFor != null && xForwardedFor.contains(",") ? xForwardedFor.split(",")[0]:xForwardedFor;
    String remoteHost = req.getRemoteHost();
    String remoteAddr = req.getRemoteAddr();
    int remotePort = req.getRemotePort();
    StringBuffer sb = new StringBuffer();
    if (remoteHost != null 
    && !"".equals(remoteHost)
    && !remoteHost.equals(remoteAddr)) {
        sb.append(remoteHost).append(" ");
    }
    if (xForwardedFor != null 
    && !"".equals(xForwardedFor)) {
        sb.append(xForwardedFor).append("(fwd)=>");
    }
    if (remoteAddr != null || !"".equals(remoteAddr)) {
        sb.append(remoteAddr).append(":").append(remotePort);
    }
    return sb.toString();
}
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