我正在攻读java考试,在过去的考试中,讲师问了这个问题,我想知道是否有人可以帮助我理解它:
在java解释线程的上下文中.举例说明何时可以使用线程.命名两个java虚拟机线程.
问题的前两部分很容易,但关于命名两个VM线程的部分实际上是让我感到困惑.
来自测试程序的简单线程转储显示以下线程 - 一个是应用程序线程,然后您有另外8个JVM线程:
Full thread dump Java HotSpot(TM) Client VM (14.0-b16 mixed mode):
"Low Memory Detector" daemon prio=6 tid=0x0aad6c00 nid=0x9c0 runnable [0x00000000]
java.lang.Thread.State: RUNNABLE
"CompilerThread0" daemon prio=10 tid=0x0aad0c00 nid=0x6d4 waiting on condition [0x00000000]
java.lang.Thread.State: RUNNABLE
"Attach Listener" daemon prio=10 tid=0x0aacb400 nid=0xda4 runnable [0x00000000]
java.lang.Thread.State: RUNNABLE
"Signal Dispatcher" daemon prio=10 tid=0x0aaca000 nid=0xcc8 waiting on condition [0x00000000]
java.lang.Thread.State: RUNNABLE
"Finalizer" daemon prio=8 tid=0x0aab7400 nid=0xba0 in Object.wait() [0x0ac2f000]
java.lang.Thread.State: WAITING (on object monitor)
at java.lang.Object.wait(Native Method)
- waiting on <0x029a0b18> (a java.lang.ref.ReferenceQueue$Lock)
at java.lang.ref.ReferenceQueue.remove(Unknown Source)
- locked <0x029a0b18> (a java.lang.ref.ReferenceQueue$Lock)
at java.lang.ref.ReferenceQueue.remove(Unknown Source)
at java.lang.ref.Finalizer$FinalizerThread.run(Unknown Source)
"Reference Handler" daemon prio=10 tid=0x0aab2c00 nid=0x418 in Object.wait() [0x0abdf000]
java.lang.Thread.State: WAITING (on object monitor)
at java.lang.Object.wait(Native Method)
- waiting on <0x029a0a20> (a java.lang.ref.Reference$Lock)
at java.lang.Object.wait(Object.java:485)
at java.lang.ref.Reference$ReferenceHandler.run(Unknown Source)
- locked <0x029a0a20> (a java.lang.ref.Reference$Lock)
"main" prio=6 tid=0x002b6400 nid=0x3d8 runnable [0x0090f000]
java.lang.Thread.State: RUNNABLE
at TestClass.main(TestClass.java:8)
"VM Thread" prio=10 tid=0x0aaafc00 nid=0x184 runnable
"VM Periodic Task Thread" prio=10 tid=0x0aad9000 nid=0xc7c waiting on condition
Run Code Online (Sandbox Code Playgroud)
虽然,YMMV因为这些结果高度依赖于您正在使用的JVM.
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