需要使用sql developer在oracle db上按日期计算记录和组计数

Question

我有一张如下表

   ID                created    sent    type
-----------------------------------------------------
0001463583000051783  31-JUL-12  1   270
0081289563000051788  01-AUG-12  1   270
0081289563000051792  01-AUG-12  1   270
0081289563000051791  01-AUG-12  1   270
0081289563000051806  01-AUG-12  1   270
0001421999000051824  06-AUG-12  1   270
0001421999000051826  06-AUG-12  1   270
0001464485000051828  06-AUG-12  1   270
0082162128000051862  09-AUG-12  2   278
0082162128000051861  09-AUG-12  2   278
0022409222082910259  09-AUG-12  3   278

我想要输出以下内容

created     Count
---------------------
31-JUL-12   1
01-AUG-12   4
06-AUG-12   3
09-AUG-12   3

在Oracle 10g上使用SQL Developer实现这一目标有多难

我已经尝试了几个查询来生成这样一个表,最后它没有按日期对计数进行分组,当我们每天平均5000-10000个事务时,只给我一个'1'计数.我可能过于复杂了.但我想要一些简单的事情,我可以在日期范围内每天提取交易量.

当我运行查询时,目前发生的事情是

created     Count
---------------------
31-JUL-12   1
01-AUG-12   1
01-AUG-12   1
01-AUG-12   1
01-AUG-12   1
06-AUG-12   1
06-AUG-12   1
06-AUG-12   1
09-AUG-12   1
09-AUG-12   1
09-AUG-12   1

Answer 1

我设法通过此查询获得此结果:

select trunc(created), count(*)
from table1
group by trunc(created)

Note the trunc function, even if you don't display it, the DATE datatype holds the time as well

Here is a fiddle