我试图在Ruby(1.8)中的method_missing中找到一种从调用者获取绑定的方法,但我似乎无法找到一种方法来实现它.
希望以下代码解释我想要做的事情:
class A
def some_method
x = 123
nonexistent_method
end
def method_missing(method, *args, &block)
b = caller_binding # <---- Is this possible?
eval "puts x", b
end
end
A.new.some_method
# expected output:
# 123
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那么......有没有办法获得调用者的绑定,或者这在Ruby(1.8)中是不可能的?
这是一个(有点脆弱)黑客攻击:
# caller_binding.rb
TRACE_STACK = []
VERSION_OFFSET = { "1.8.6" => -3, "1.9.1" => -2 }[RUBY_VERSION]
def caller_binding(skip=1)
TRACE_STACK[ VERSION_OFFSET - skip ][:binding]
end
set_trace_func(lambda do |event, file, line, id, binding, classname|
item = {:event=>event,:file=>file,:line=>line,:id=>id,:binding=>binding,:classname=>classname}
#p item
case(event)
when 'line'
TRACE_STACK.push(item) if TRACE_STACK.empty?
when /\b(?:(?:c-)?call|class)\b/
TRACE_STACK.push(item)
when /\b(?:(?:c-)?return|end|raise)\b/
TRACE_STACK.pop
end
end)
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这适用于您的示例,但我还没有用其他方法测试它
require 'caller_binding'
class A
def some_method
x = 123
nonexistent_method
end
def method_missing( method, *args, &block )
b = caller_binding
eval "puts x", b
end
end
x = 456
A.new.some_method #=> prints 123
A.new.nonexistent_method #=> prints 456
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当然,如果绑定没有定义您要评估的变量,这将不起作用,但这是绑定的一般问题.如果未定义变量,则不知道它是什么.
require 'caller_binding'
def show_x(b)
begin
eval <<-SCRIPT, b
puts "x = \#{x}"
SCRIPT
rescue => e
puts e
end
end
def y
show_x(caller_binding)
end
def ex1
y #=> prints "undefined local variable or method `x' for main:Object"
show_x(binding) #=> prints "undefined local variable or method `x' for main:Object"
end
def ex2
x = 123
y #+> prints "x = 123"
show_x(binding) #+> prints "x = 123"
end
ex1
ex2
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要解决这个问题,您需要在评估的字符串中进行一些错误处理:
require 'caller_binding'
def show_x(b)
begin
eval <<-SCRIPT, b
if defined? x
puts "x = \#{x}"
else
puts "x not defined"
end
SCRIPT
rescue => e
puts e
end
end
def y
show_x(caller_binding)
end
def ex1
y #=> prints "x not defined"
show_x(binding) #=> prints "x not defined"
end
def ex2
x = 123
y #+> prints "x = 123"
show_x(binding) #+> prints "x = 123"
end
ex1
ex2
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