当一个XSLT导入另一个XSLT时,MalformedURLException

Question

我遇到一个问题,其中一个XSLT文件导入另一个,导致我的应用程序抛出MalformedURLException.import语句main.xsl如下所示:

<xsl:import href="transformCommon.xsl"/>

该文件transformCommon.xsl与...相同main.xsl.限制加载它的代码如下所示:

private void loadXSLTFiles(String xsltFile)
{
    TransformerFactory transformFactory = TransformerFactory.newInstance();  

    //tell the location of all of import file 
    transformFactory.setURIResolver(new ClassPathURIResolver());

    Templates cache=null;

    //cache XSLT source file for transformation reuse
    InputStream is = this.getClass().getClassLoader().getResourceAsStream(xsltFile);
    javax.xml.transform.Source xsltSource = new javax.xml.transform.stream.StreamSource(is);

    try
    {
        cache = transformFactory.newTemplates(xsltSource);
    }
    catch (TransformerConfigurationException domException)
    {
        LOG.logError("XSLT initialization error has occurred: " + domException.getMessage());
    }
    ...

堆栈跟踪是:

Caused by: java.net.MalformedURLException
    at java.net.URL.(URL.java:602)
    at java.net.URL.(URL.java:465)
    at java.net.URL.(URL.java:414)
    at org.apache.xerces.impl.XMLEntityManager.setupCurrentEntity(Unknown Source)
    at org.apache.xerces.impl.XMLVersionDetector.determineDocVersion(Unknown Source)
    at org.apache.xerces.parsers.XML11Configuration.parse(Unknown Source)
    at org.apache.xerces.parsers.XML11Configuration.parse(Unknown Source)
    at org.apache.xerces.parsers.XMLParser.parse(Unknown Source)
    at org.apache.xerces.parsers.AbstractSAXParser.parse(Unknown Source)
    at org.apache.xerces.jaxp.SAXParserImpl$JAXPSAXParser.parse(Unknown Source)
    at org.apache.xalan.templates.StylesheetRootProxy.(Unknown Source)
    ... 59 more

我不确定为什么会出现这个错误.当我从中删除导入时main.xsl,一切正常.当然,删除它不是一种选择,因为这一点的重点是将常用函数移动到单独的XSLT.

有趣的是,只有我的工作站似乎有这个问题.最初编写此代码的开发人员说他没有遇到任何问题.我正在使用RAD 7.5.有没有人知道如何在逐个工作站的基础上出现这个问题？

Answer 1

为了能够解析样式表中的相对URL(包括导入)Source,您Templates需要从中创建"系统ID"(即.xsl文件的URL ).

代替

//tell the location of all of import file 
transformFactory.setURIResolver(new ClassPathURIResolver());

//cache XSLT source file for transformation reuse
InputStream is = this.getClass().getClassLoader().getResourceAsStream(xsltFile);
javax.xml.transform.Source xsltSource = new javax.xml.transform.stream.StreamSource(is);

试试这个:

URL xsltURL = this.getClass().getClassLoader().getResource(xsltFile);
Source xsltSource = new StreamSource(xsltURL.openStream(),
                                     xsltURL.toExternalForm());

(openStream可以抛出,IOException所以你需要将它添加到你的throws或在try/catch中包装整个东西).