Bru*_*los 1 iphone nsmutablearray nsmutabledictionary ios
我有一个NSMutableArray类型的对象NSMutableDictionary,
在NSMutableDictionary包含2个键
- 航空公司(String)
-Rating(整数)
我有一个NSMutableArray所有的对象,我需要的是总结所有航空公司重复对象的评级,一个例子:
Airline Rating
A 2
B 3
B 4
C 5
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最终结果数组将是A = 2,C = 5和B的总和等于7.
我的代码到目前为止:
for (int i = 0; i < arrayMealRating.count; ++i) {
NSMutableDictionary *item = [arrayMealRating objectAtIndex:i];
NSLog(@"item=%@",item);
for (int j = i+1; j < arrayMealRating.count; ++j)
{
if ([[item valueForKey:@"Airline"] isEqualToString:[arrayMealRating objectAtIndex:j]]){
NSMutableDictionary *item = [arrayMealRating objectAtIndex:j];
NSMutableDictionary *item1 = [arrayMealRating objectAtIndex:i];
NSInteger auxCount = [[item valueForKey:@"setMealRating"] integerValue] + [[item1 valueForKey:@"setMealRating"] integerValue];
NSMutableDictionary *aux = [NSMutableDictionary dictionaryWithObjectsAndKeys:[item valueForKey:@"Airline"], @"Airline"
,[NSString stringWithFormat:@"%d",auxCount], @"setMealRating"
,nil];
NSLog(@"aux=%@",aux);
[arrayMealRating replaceObjectAtIndex:i withObject:aux];
}
}
}
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我知道有点乱,但我不知道如何使用NSMutableDictionary,任何帮助将不胜感激,在此先感谢!
如果您不想改变存储数据的方式,那么您将如何使用键值编码来实现它.下面是@distinctUnionOfObjects和@sum文档的直接链接.
// Get all the airline names with no duplicates using the KVC @distinctUnionOfObjects collection operator
NSArray *airlineNames = [arrayMealRating valueForKeyPath:@"@distinctUnionOfObjects.Airline"];
// Loop through all the airlines
for (NSString *airline in airlineNames) {
// Get an array of all the dictionaries for the current airline
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"(Airline == %@)", airline];
NSArray *airlineMealRating = [arrayMealRating filteredArrayUsingPredicate:predicate];
// Get the sum of all the ratings using KVC @sum collection operator
NSNumber *rating = [airlineMealRating valueForKeyPath:@"@sum.Rating"];
NSLog(@"%@: %@", airline, rating);
}
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这给出了以下输出
A: 2
B: 7
C: 5
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