Ala*_*laa 8 sql t-sql sql-server pivot
我在行样式中有一个Profiles store配置文件属性值的表,例如:
[ProfileID] [PropertyDefinitionID] [PropertyValue]
1 6 Jone
1 7 Smith
1 8 Mr
1 3 50000
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和另一个属性定义表:
[PropertyDefinitionID] [PropertyName]
6 FirstName
7 LastName
8 Prefix
3 Salary
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如何使用PIVOT
或以任何其他方式以这种方式显示它:
[ProfileID] [FirstName] [LastName] [Salary]
1 Jone Smith 5000
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Rom*_*kar 12
没有PIVOT
关键字,只需按分组即可轻松完成此操作
select
P.ProfileID,
min(case when PD.PropertyName = 'FirstName' then P.PropertyValue else null end) as FirstName,
min(case when PD.PropertyName = 'LastName' then P.PropertyValue else null end) as LastName,
min(case when PD.PropertyName = 'Salary' then P.PropertyValue else null end) as Salary
from Profiles as P
left outer join PropertyDefinitions as PD on PD.PropertyDefinitionID = P.PropertyDefinitionID
group by P.ProfileID
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你也可以用PIVOT
关键字来做到这一点
select
*
from
(
select P.ProfileID, P.PropertyValue, PD.PropertyName
from Profiles as P
left outer join PropertyDefinitions as PD on PD.PropertyDefinitionID = P.PropertyDefinitionID
) as P
pivot
(
min(P.PropertyValue)
for P.PropertyName in ([FirstName], [LastName], [Salary])
) as PIV
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更新:对于动态数量的属性 - 请查看SQL SELECT语句中的Increment值
看起来你可能有一个未知数量的PropertyName's
你需要变成列.如果是这种情况,那么您可以使用动态SQL生成结果:
DECLARE @cols AS NVARCHAR(MAX),
@query AS NVARCHAR(MAX)
select @cols = STUFF((SELECT distinct ',' + QUOTENAME(PropertyName)
from propertydefinitions
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set @query = 'SELECT profileid, ' + @cols + ' from
(
select p.profileid,
p.propertyvalue,
d.propertyname
from profiles p
left join propertydefinitions d
on p.PropertyDefinitionID = d.PropertyDefinitionID
) x
pivot
(
max(propertyvalue)
for propertyname in (' + @cols + ')
) p '
execute(@query)
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