Pra*_*mod 5 php ajax google-visualization drop-down-menu
我必须根据下拉值显示google图表，其中包含商店ID我正在从mysql检索数据，值没有问题，我正在根据ajax的商店ID检索数据，只是在输入框中确认它是还可以。
但我不知道如何用这些值更新该图表，而无需重新加载页面。这是我的带有硬编码值的Google图表代码。
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>newChart</title>
<script type="text/javascript" src="https://www.google.com/jsapi"></script>
<script type="text/javascript">
google.load("visualization", "1", {packages:["corechart"]});
google.setOnLoadCallback(drawChart);
function drawChart()
{var data = google.visualization.arrayToDataTable([['Company & Model', 'Views'],['Samsung Hero Music E1232B',5],['Samsung Galaxy Y S5360',7],['Samsung Galaxy Ace S5830',7],['Karbonn K 1212',2],]);
var options = {
title: 'Most Popular Item ',
hAxis: {title: 'Brand', titleTextStyle: {color: 'red'}}};
var chart = new google.visualization.ColumnChart(document.getElementById('MPI_chart_div'));
chart.draw(data, options);
}
</script>
</head>
<body>
<h3>COLUMN CHART FOR MOST POPULAR ITEM </h3>
Select Shop <select id="MPI_selected_shop" onchange="MPI_set_shop(this.value);">
<option value="all_Shops">All Shops</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
</select>
<input type="text" id="sd" />
<div id="MPI_chart_div" style="width: 800px; height: 400px;"></div>
</body>
</html>
这是我在脚本标签内同一页面中的ajax代码
var xmlHttp
function MPI_set_shop(str)
{
alert(str);
xmlHttp=GetXmlHttpObject();
if (xmlHttp==null)
{
alert ("Your browser does not support AJAX!");
return;
}
var url="chart.php";
url=url+"?q="+str;
alert(url);
xmlHttp.onreadystatechange=stateChanged;
xmlHttp.open("GET",url,true);
xmlHttp.send(null);
}
function stateChanged()
{
if (xmlHttp.readyState==4)
{
document.getElementById("sd").value=xmlHttp.responseText;
$st=xmlHttp.responseText;
alert($st);
}
}
这是我的chart.php，我从这里使用ajax从mysql获取格式化数据
<?php
$testid=0;
$testid=$_REQUEST["q"];
//echo $testid;
$con = mysql_connect("localhost","root","");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
// Select Database
mysql_select_db("mysql", $con) or die('Could not connect: ' . mysql_error());;
$qMostPopularItem = "SELECT t.pr_id,p.pdt_company_name,p.pdt_model_name,SUM(t.count) AS count FROM tmp AS t INNER JOIN product_mapping AS p ON t.pr_id = p.pr_id AND t.shop_id =$testid GROUP BY pr_id ORDER BY t.count DESC;";
$mpi = mysql_query($qMostPopularItem,$con) or die('Could not fetch MPI: ' . mysql_error());
while($infoMPISW = mysql_fetch_assoc($mpi))
{
echo "['".$infoMPISW['pdt_company_name']." ";
echo $infoMPISW['pdt_model_name'] ."',";
echo $infoMPISW['count'],"],";
}
?>
在 Ajax 响应上，使用新值再次调用 drawChart() 函数。下面是我尝试过的代码。
索引文件
<script type="text/javascript" src="https://www.google.com/jsapi"></script>
<script type="text/javascript">
google.load("visualization", "1", {packages:["corechart"]});
google.setOnLoadCallback(drawChart);
function drawChart()
{
alert('called');
var data = google.visualization.arrayToDataTable([['Company & Model', 'Views'],['Samsung Hero Music E1232B',5],['Samsung Galaxy Y S5360',7],['Samsung Galaxy Ace S5830',7],['Karbonn K 1212',2],]);
var options = {
title: 'Most Popular Item ',
hAxis: {title: 'Brand', titleTextStyle: {color: 'red'}}};
var chart = new google.visualization.ColumnChart(document.getElementById('MPI_chart_div'));
chart.draw(data, options);
}
function drawChart2()
{
alert('called2');
var data = google.visualization.arrayToDataTable([['Company & Model', 'Views'],['Samsung Music E1232B',5],['Samsung S5360',7],['Samsung S5830',7],['Karbonn K 1212',2],]);
var options = {
title: 'Most Popular Item ',
hAxis: {title: 'Brand', titleTextStyle: {color: 'red'}}};
var chart = new google.visualization.ColumnChart(document.getElementById('MPI_chart_div'));
chart.draw(data, options);
}
</script>
<script>
var xmlHttp
function MPI_set_shop(str)
{
alert(str);
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
alert(xmlhttp.responseText);
//google.load("visualization", str, {packages:["corechart"]});
//google.setOnLoadCallback(drawChart);
drawChart2(); // Note down here..
}
}
xmlhttp.open("GET","chart.php?q="+str,true);
xmlhttp.send();
}
</script>
<h3>COLUMN CHART FOR MOST POPULAR ITEM </h3>
Select Shop <select id="MPI_selected_shop" onchange="MPI_set_shop(this.value);">
<option value="all_Shops">All Shops</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
</select>
<input type="text" id="sd" />
<div id="MPI_chart_div" style="width: 800px; height: 400px;"></div>
请注意，我创建了另一个名为drawChart2()的函数，但如果您调用drawChart()，那么它也会向您发出“called”警报。您只需在其中传递新值即可。希望以上回答对您有所帮助。最重要的是，除了回调函数之外，我什么也没做。[虽然我更改了 javascript ajax 代码，但这不会有任何问题。]
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