我正在寻找一种方法来在调用异步服务时自动显示和隐藏"加载"消息,所以不要这样做:
showLoadingWidget();
service.getShapes(dbName, new AsyncCallback() {
public void onSuccess(Shape[] result) {
hideLoadingWidget();
// more here...
}
public void onFailure(Throwable caught) {
hideLoadingWidget();
//more here
}
});
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我想这样做,但仍然在完成时显示和隐藏消息.
// this should be gone: showLoadingWidget();
service.getShapes(dbName, new AsyncCallback() {
public void onSuccess(Shape[] result) {
// this should be gone: hideLoadingWidget();
// more here...
}
public void onFailure(Throwable caught) {
//this should be gone: hideLoadingWidget();
//more here
}
});
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总之,我想改变异步调用的行为.感谢您提出所有可能的建议.
丹尼尔
Dav*_*ker 19
您可以将调用本身包装在处理显示加载消息的对象中,可能会在错误或其他情况下重试几次.像这样的东西:
public abstract class AsyncCall<T> implements AsyncCallback<T> {
/** Call the service method using cb as the callback. */
protected abstract void callService(AsyncCallback<T> cb);
public void go(int retryCount) {
showLoadingMessage();
execute(retryCount);
}
private void execute(final int retriesLeft) {
callService(new AsyncCallback<T>() {
public void onFailure(Throwable t) {
GWT.log(t.toString(), t);
if (retriesLeft <= 0) {
hideLoadingMessage();
AsyncCall.this.onFailure(t);
} else {
execute(retriesLeft - 1);
}
}
public void onSuccess(T result) {
hideLoadingMessage();
AsyncCall.this.onSuccess(result);
}
});
}
public void onFailure(Throwable t) {
// standard error handling
}
...
}
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要拨打电话,请执行以下操作:
new AsyncCall<DTO>() {
protected void callService(AsyncCallback<DTO> cb) {
DemoService.App.get().someService("bla", cb);
}
public void onSuccess(DTO result) {
// do something with result
}
}.go(3); // 3 retries
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您可以使用代码扩展它以检测需要很长时间的呼叫并显示某种繁忙指示等.
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