Trac sqlite日期查询

Question

我有一段时间生成一份报告,其中包含我的门票创建日期.

这是我的sqlite查询(我直接查询数据库)

.header on
.mode csv
.output opentickets.csv
SELECT DISTINCT
   id AS ticket, summary, status, priority, t.type AS type, 
   owner, time as created

  FROM ticket t, ticket_custom q
  LEFT JOIN enum p ON p.name = t.priority AND p.type = 'priority'
  WHERE t.id = q.ticket AND status <> 'closed'
 ORDER BY  priority, time;

但是我在创作时获得的价值是垃圾:当我得到2012-07-03时,我得到1341324096360000

我试过unix epoch时间转换...查询:

.header on
.mode csv
.output opentickets.csv
SELECT DISTINCT
   id AS ticket, summary, status, priority, t.type AS type, 
   owner, datetime(time, 'unixepoch') as created

  FROM ticket t, ticket_custom q
  LEFT JOIN enum p ON p.name = t.priority AND p.type = 'priority'
  WHERE t.id = q.ticket AND status <> 'closed'
 ORDER BY  priority, time;

我得到:-1413-03-01 13:07:12

我错过了什么？

Answer 1

CL是正确的,时间以微秒为单位存储.您可以在架构中看到时间字段为int64,在.12的发行说明中,表示它们已将时间从"自纪元以来的秒数"更改为"自纪元以来的微秒".

至于我在Trac查询中显示时间的经验,我没有做任何转换.这是一个查询,用于显示过去7天内所有已更改的票证.如您所见,我将票证更改时间显示为select和Trac正确格式化的一部分.Trac会自动将创建,修改,日期,时间字段格式化为日期和/或时间.有关详细信息,请参阅此Trac wiki页面.

    SELECT 
tc.Ticket AS ticket, 
tc.Time as time, 
c.value as  __group__,
ifnull(tc.Newvalue,0) as total,
tc.Author  AS author,         
tc.Field as field     
from ticket_change tc 
LEFT JOIN ticket t on t.id = tc.ticket
LEFT JOIN ticket_custom c on c.ticket = tc.ticket and c.name= 'customer'
LEFT JOIN ticket_custom tt on tt.ticket = tc.ticket and tt.name = 'totalhours'
where field = 'hours' and c.Value is not null
and tc.Time > strftime('%s',CURRENT_DATE-7) +0
and tc.Time < strftime('%s',CURRENT_DATE) +0
and tc.Author = $USER
and tt.value is not null

如果你想做一些特殊的fomatting,请按时查看SQLite文档,但这是一个简单的例子

strftime('%m/%d/%Y', time / 1000000, 'unixepoch', 'localtime') 

我希望这有帮助.