redis可以禁用流水线命令的回复吗？

Question

我正在开发一个缓存,需要为每个调用增加几百个计数器,如下所示:

redis.pipelined do
  keys.each{ |key| redis.incr key }
end

在我的分析中,我看到我不需要的回复仍然被redis宝石收集并浪费了一些有价值的时间.我能以某种方式告诉redis我对回复不感兴趣吗？有没有更好的方法来增加很多值.

我没有找到MINCR命令,例如..

提前致谢!

Answer 1

是的......至少在2.6中.您可以在LUA脚本中执行此操作,只需让LUA脚本返回空结果即可.这是使用booksleeve客户端:

const int DB = 0; // any database number
// prime some initial values
conn.Keys.Remove(DB, new[] {"a", "b", "c"});
conn.Strings.Increment(DB, "b");
conn.Strings.Increment(DB, "c");
conn.Strings.Increment(DB, "c");

// run the script, passing "a", "b", "c", "c" to
// increment a & b by 1, c twice
var result = conn.Scripting.Eval(DB,
    @"for i,key in ipairs(KEYS) do redis.call('incr', key) end",
    new[] { "a", "b", "c", "c"}, // <== aka "KEYS" in the script
    null); // <== aka "ARGV" in the script

// check the incremented values
var a = conn.Strings.GetInt64(DB, "a");
var b = conn.Strings.GetInt64(DB, "b");
var c = conn.Strings.GetInt64(DB, "c");

Assert.IsNull(conn.Wait(result), "result");
Assert.AreEqual(1, conn.Wait(a), "a");
Assert.AreEqual(2, conn.Wait(b), "b");
Assert.AreEqual(4, conn.Wait(c), "c");

或者做同样的事情incrby,将"by"数字作为参数传递,将中间部分更改为:

// run the script, passing "a", "b", "c" and 1, 1, 2
// increment a & b by 1, c twice
var result = conn.Scripting.Eval(DB,
    @"for i,key in ipairs(KEYS) do redis.call('incrby', key, ARGV[i]) end",
    new[] { "a", "b", "c" }, // <== aka "KEYS" in the script
    new object[] { 1, 1, 2 }); // <== aka "ARGV" in the script