使用rest-client ruby​​ gem在elasticsearch get请求中传递json数据

Question

如何使用rest client 执行以下查询(在doc中给出).

curl -XGET 'http://localhost:9200/twitter/tweet/_search' -d '{
    "query" : {
        "term" : { "user" : "kimchy" }
    }
}
'

我试过这样做:

q = '{
    "query" : {
        "term" : { "user" : "kimchy" }
    }
}
'

r = JSON.parse(RestClient.get('http://localhost:9200/twitter/tweet/_search', q))

这引发了一个错误:

in `process_url_params': undefined method `delete_if' for #<String:0x8b12e18>     (NoMethodError)
    from /home/socialapps/.rvm/gems/ruby-1.9.3-p194/gems/rest-client-1.6.7/lib/restclient/request.rb:40:in `initialize'
    from /home/socialapps/.rvm/gems/ruby-1.9.3-p194/gems/rest-client-1.6.7/lib/restclient/request.rb:33:in `new'
    from /home/socialapps/.rvm/gems/ruby-1.9.3-p194/gems/rest-client-1.6.7/lib/restclient/request.rb:33:in `execute'
    from /home/socialapps/.rvm/gems/ruby-1.9.3-p194/gems/rest-client-1.6.7/lib/restclient.rb:68:in `get'
    from get_check2.rb:12:in `<main>'

当我使用相同的时候RestClient.post,它给了我正确的结果!但是elasticsearch doc XGET在curl命令中使用搜索查询而不是XPOST.如何使该RestClient.get方法工作？

如果有其他/更好的方法来执行此操作,请建议.

Answer 1

RestClient无法发送请求主体GET.你有两个选择:

将您的查询作为sourceURL参数传递:

require 'rest_client'
require 'json'

# RestClient.log=STDOUT # Optionally turn on logging

q = '{
    "query" : { "term" : { "user" : "kimchy" } }
}
'
r = JSON.parse \
      RestClient.get( 'http://localhost:9200/twitter/tweet/_search',
                      params: { source: q } )

puts r

......或者只是使用POST.

更新:修复了URL参数的错误传递,注意params哈希.