Mua*_*ani 20 html forms jquery json
我试图将HTML表单数据转换为JSON对象,我有这个线程,但我不知道为什么它不适合我.我使用以下代码.
<form id="myform" action="" method="post">
<div class="form-field">
<label for="title">Title</label>
<input name="title" id="title" type="text" value="" size="40" aria-required="true">
</div>
<div class="form-field form-required">
<label for="your-name">Your Name</label>
<input name="yourName" id="yourName" type="text" value="" size="40" aria-required="true">
</div>
<div class="form-field">
<label for="contact-no">Contact No:</label>
<input name="contact" id="contact" type="text" value="" size="40" aria-required="true">
</div>
<div class="form-field">
<label for="description">Description:</label>
<textarea name="description" id="description" rows="1" cols="40" aria-required="true"></textarea>
</div>
<div class="form-field">
<label for="email">Email:</label>
<input name="email" id="email" type="text" value="optional" size="40" aria-required="true">
</div>
<div class="form-field">
<label for="city">City:</label>
<input name="city" id="city" type="text" value="" size="40" aria-required="true">
</div>
<div class="form-field">
<label for="country">Country:</label>
<input name="country" id="country" type="text" value="" size="40" aria-required="true">
</div>
<div class="form-field">
<label for="pic1">Picture 1:</label>
<input type="file" name="pic1" id="pic1">
</div>
<div class="form-field">
<label for="pic2">Picture 2:</label>
<input type="file" name="pic2" id="pic2">
</div>
<div class="form-field">
<label for="pic3">Picture 3:</label>
<input type="file" name="pic3" id="pic3">
</div>
<div class="form-field">
<label for="pic4">Picture 4:</label>
<input type="file" name="pic4" id="pic4">
</div>
<div class="form-field">
<label for="pic5">Picture 5:</label>
<input type="file" name="pic5" id="pic5">
</div>
<div class="form-field">
<label for="demand">Your Demand:</label>
<input name="demand" id="demand" type="text" value="" size="40" aria-required="true">
</div>
<p class="submit">
<input type="submit" name="postAd" id="postAd" class="button" value="Post Ad For Review">
</p>
<div id="results">hello</div>
</form>
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$(document).ready(function(){
$.fn.serializeObject = function() {
var o = {};
var a = this.serializeArray();
$.each(a, function() {
if (o[this.name] === undefined) {
if (!o[this.name].push) {
o[this.name] = [o[this.name]];
}
o[this.name].push(this.value || '');
} else {
alert(this.name);
o[this.name] = this.value || '';
}
});
return o;
};
$('#myform').submit(function() {
$('#result').text(JSON.stringify($('#myform').serializeObject()));
return false;
});
});
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我试着调试它,我注意到当我的函数运行时,它总是在else语句中运行代码.
Dav*_*ave 18
我在JSFiddle中添加了上面的表单,它将JSON数据显示为输出.
$(function() {
$('form').submit(function() {
$('#result').text(JSON.stringify($('form').serializeObject()));
return false;
});
});
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使用这个 jQuery 插件 .serializeJSON()将表单数据转换为 JSON 对象。
<form id="my-profile">
<!-- simple attribute -->
<input type="text" name="fullName" value="Mario Izquierdo" />
<!-- nested attributes -->
<input type="text" name="address[city]" value="San Francisco" />
<input type="text" name="address[state][name]" value="California" />
<input type="text" name="address[state][abbr]" value="CA" />
</form>
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Javascript:
$('#my-profile').serializeJSON();
// returns =>
{
fullName: "Mario Izquierdo",
address: {
city: "San Francisco",
state: {
name: "California",
abbr: "CA"
}
}
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serializeJSON() 函数返回一个 JSON 对象。
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