使用jquery在相同的ajax请求中发送和接收数据

Question

发送数据和接收依赖于该数据的响应的最佳方法是什么？

考虑用于请求的PHP文件:

$test = $_POST['test'];

echo json_encode($test);

我试图通过以下方式实现这一目标:

$.ajax({
    type: "POST",
    dataType: "json",
    data: '{test : worked}',
    url: 'ajax/getDude.php',
    success: function(response) {
        alert(response);
    }
});

Answer 1

丢失引号以传递对象:

$.ajax({
  type: "POST",
  dataType: "json",
  data: {test : worked},
  url: 'ajax/getDude.php',
  success: function(data) {
    alert(data);
  }
});

Answer 2

而不是这个

data: '{test : worked}'

尝试

data: {"test" : worked} // Worked being your data you want to pass..
 data: {"test" : "worked"} // Else enclose worked in quotes