gag*_*ina 1 python dictionary list
class MyOwnClass:
# list who contains the queries
queries = []
# a template dict
template_query = {}
template_query['name'] = 'mat'
template_query['age'] = '12'
obj = MyOwnClass()
query = obj.template_query
query['name'] = 'sam'
query['age'] = '23'
obj.queries.append(query)
query2 = obj.template_query
query2['name'] = 'dj'
query2['age'] = '19'
obj.queries.append(query2)
print obj.queries
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它给了我
[{'age': '19', 'name': 'dj'}, {'age': '19', 'name': 'dj'}]
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虽然我希望有
[{'age': '23' , 'name': 'sam'}, {'age': '19', 'name': 'dj'}]
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我想为这个列表使用一个模板,因为我会经常使用它,并且有一些默认变量不需要更改.
为什么这样做会改变template_query自己?我是python的新手,我很困惑.
这是因为你每次指向同一个字典......并覆盖密钥......
# query = obj.template_query - dont need this
query = {}
query['name'] = 'sam'
query['age'] = '23'
obj.queries.append(query)
query2 = {} #obj.template_query-dont need this
query2['name'] = 'dj'
query2['age'] = '19'
obj.queries.append(query2)
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这应该证明你的问题
>>> q = {'a':1}
>>> lst = []
>>> lst.append(q)
>>> q['a']=2
>>> lst
[{'a': 2}]
>>> lst.append(q)
>>> lst
[{'a': 2}, {'a': 2}]
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你可以用不同的方式实现你的类
class MyOwnClass:
# a template dict
@property
def template_query():
return {'name':'default','age':-1}
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这将使obj.template_query每次返回一个新的词典