iOS如何知道UITableView中是否第二次点击了一行？

Question

我正在开发一个iOS 5应用程序,在我的情况下,如果用户第一次从UITableView点击一行然后它将执行一些操作,如果它被第二次点击,那么它将执行不同的操作.

现在,问题是如何知道特定行是否第二次被点击？

提前致谢!!

Answer 1

那你为什么不在桌面视图中使用UIGestures.这将是最容易解决的问题,对我来说就像魅力一样.

以下代码将帮助您在代码中实现它:

    // Put this code in your ViewDidLoad:
    UITapGestureRecognizer *doublegesture = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(didTableViewCellDoubleTapping:)];
    doublegesture.numberOfTapsRequired = 2;
    [roomTableView addGestureRecognizer:doublegesture];
    [doublegesture release];

//在双击时处理事件的方法

-(void)didTableViewCellDoubleTapping:(UITapGestureRecognizer *)gestureRecognizer 
{
    if (gestureRecognizer.state == UIGestureRecognizerStateEnded) {
        CGPoint swipeLocation = [gestureRecognizer locationInView:roomTableView];
        NSIndexPath *swipedIndexPath = [roomTableView indexPathForRowAtPoint:swipeLocation];
        NSLog(@"%d",swipedIndexPath.row);
                
        // ... Here you can add your logic
    }
}

以类似的方式,如果您为单次点击添加另一个UIGesture

 UITapGestureRecognizer *gesture = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(didTableViewSingleCellTapping:)];
    gesture.numberOfTapsRequired = 1;
    [roomTableView addGestureRecognizer:gesture];
    [gesture release];
    
    [gesture requireGestureRecognizerToFail:doublegesture];

-(void)didTableViewSingleCellTapping:(UITapGestureRecognizer *)gestureRecognizer 
{
    if (gestureRecognizer.state == UIGestureRecognizerStateEnded) {
        CGPoint swipeLocation = [gestureRecognizer locationInView:roomTableView];
        NSIndexPath *swipedIndexPath = [roomTableView indexPathForRowAtPoint:swipeLocation];
        
        NSLog(@"%d",swipedIndexPath.row);
    }
}