实现一个连续广播到其邻居的简单UDP网络

Question

1. 我有3个节点A,B和C及其各自的端口号.
2. 我正在尝试编写一个java程序,它接受3个参数:它的节点名称和它的2个相邻节点的端口,"Hello I'm A"并向它们广播一个字符串(所以A将广播到B和C).它将每3秒执行一次.
3. 该程序将在3个独立的实例中运行.
4. 收到一个字符串后,它将打印它收到的节点"Received string"(例如,端口B).

我很难实现这个,但我听说过multicasting用UDP 调用的东西.到目前为止,这是我的工作,我做错了什么？

class UDP {
    public static void main(String[] args) throws Exception {
        String nodeName = args[0];
        int neighbourPort1 = Integer.valueOf(args[1]);
        int neighbourPort2 = Integer.valueOf(args[2]);

        while(true) {
            Thread.sleep(3000); //every 3 seconds
            //Continously broadcast and listen to neighbour1
            DatagramSocket socket1 = null;
            try {
                //CREATE SOCKET TO NEIGHBOUR1
                InetAddress host = InetAddress.getByName("localhost");
                socket1 = new DatagramSocket();
                socket1.connect(host, neighbour1);

                //CREATE DATAGRAMS FOR SENDING
                String message = "Hello I'm " + nodeName;
                byte[] sendData = message.getBytes();
                DatagramPacket sendPacket = new DatagramPacket(sendData, sendData.length, host, port);
                socket1.send(sendPacket);

                //CREATE DATAGRAMS FOR RECEIVING
                byte[] receiveData = new byte[100]; //is there a way to determine the needed space?
                DatagramPacket receivePacket = new DatagramPacket(receiveData, receiveData.length);
                socket1.receive(receivePacket);
                System.out.println("Received string");

            } catch(Exception e) { }
            //Do the same for neighbour2, code is basically identical except for variables
            DatagramSocket socket2 = null;
            try {
                //CREATE SOCKET TO NEIGHBOUR2
                InetAddress host = InetAddress.getByName("localhost");
                socket2 = new DatagramSocket();
                socket2.connect(host, neighbour2);

                //FOR SENDING DATAGRAMS
                String message = "Hello I'm " + nodeName;
                byte[] sendData = message.getBytes();
                DatagramPacket sendPacket = new DatagramPacket(sendData, sendData.length, host, port);
                socket2.send(sendPacket);

                //FOR RECEIVING DATAGRAMS
                byte[] receiveData = new byte[100]; //is there a way to determine the needed space?
                DatagramPacket receivePacket = new DatagramPacket(receiveData, receiveData.length);
                socket2.receive(receivePacket);
                System.out.println("Received string");

            } catch(Exception e) { }
        }

    }
}

我知道我接近解决方案.我能够正常播放,但这是我不断倾听的部分.

Answer 1

我认为最好使用单独的线程来监听自己端口上的数据。

• A向B发送数据并阻塞，直到从B收到数据包为止。
• B向C发送数据并阻塞，直到从C收到数据包为止。
• C向A发送数据并阻塞，直到从A收到数据包为止。

每个节点都在互相等待。只需发送数据包并等待 3 秒即可。另一个线程只会监听。

public class UDP {

    public static void main(String[] args) throws Exception {
        final String nodeName = args[0];
        final int ownPort = Integer.valueOf(args[1]);
        final int neighbourPort1 = Integer.valueOf(args[2]);
        final int neighbourPort2 = Integer.valueOf(args[3]);


        // Don't create a new socket every time
        DatagramSocket neighbour1 = new DatagramSocket();
        DatagramSocket neighbour2 = new DatagramSocket();

        neighbour1.connect(InetAddress.getLocalHost(), neighbourPort1);
        neighbour2.connect(InetAddress.getLocalHost(), neighbourPort2);

        // You have to LISTEN
        new Thread() {
            @Override
            public void run() {
                try {
                    DatagramSocket socket = new DatagramSocket(ownPort);

                    byte[] buffer = new byte[socket.getReceiveBufferSize()];
                    DatagramPacket packet = new DatagramPacket(buffer, buffer.length);

                    while (true) {
                        // Blocks until it gets a packet
                        socket.receive(packet);

                        System.out.println("Received string");
                    }

                    // socket.close();
                } catch (final Exception e) {
                    e.printStackTrace();
                }
            }
        }.start();

        while (true) {
            Thread.sleep(3000);

            sendPacket(neighbour1, nodeName);
            sendPacket(neighbour2, nodeName);
        }

        // If you're not using an infinite loop:
        // neighbour1.close();
        // neighbour2.close();
    }

    private static void sendPacket(DatagramSocket to, String from) throws Exception {
        String message = "Hello I'm " + from;
        byte[] data = message.getBytes();

        DatagramPacket packet = new DatagramPacket(data, data.length);
        to.send(packet);
    }

}