Col*_*mbo 1 c++ ofstream mkdir
我正在开发一个程序,它创建2000个目录并在每个目录中放入一个文件(只有10KB左右的文件).我正在使用mkdir制作dirs和ofstream(我也试过fopen)将文件写入固态驱动器(我正在进行速度测试以进行比较).
当我运行代码时,目录创建正常但文件在写入1000左右后停止写入.我尝试在每次写入之前设置一个延迟,以防它出现某种过载,并尝试使用fopen代替ofstream,但它总是停止在第1000个文件标记周围写入文件.
这是写入文件和退出的代码,告诉我它失败了哪个文件.
fsWriteFiles.open(path, ios::app);
if(!fsWriteFiles.is_open())
{
cout << "Fail at point: " << filecount << endl;
return 1;
}
fsWriteFiles << filecontent;
fsWriteFiles.close();
Run Code Online (Sandbox Code Playgroud)
有没有人有这方面的经验或有任何理论?
这是完整的代码:此代码从随机数创建一个2位十六进制目录,然后从随机数创建一个4位十六进制目录,然后将文件存储在该目录中.在写完1000个文件后,它以"失败点"(我已经添加了一个cout)退出.这表示它无法创建文件,但它应该已经检查过该文件不存在.有时它从0开始失败,从底线击中第二个(文件已存在的else子句).任何帮助赞赏,我觉得这是与我正在尝试创建已经存在的文件,但我的文件存在检查已经不知何故滑落.有没有办法为失败的文件创建尝试获取错误消息?
int main()
{
char charpart1[3] = "";
char charpart3[5] = "";
char path[35] = "";
int randomStore = 0;
//Initialize random seed
srand(time(NULL));
struct stat buffer ;
//Create output file streams
ofstream fsWriteFiles;
ifstream checkforfile;
//Loop X times
int dircount = 0;
while(dircount < 2000)
{
path[0] = '\0'; //reset the char array that holds the path
randomStore = rand() % 255;
sprintf(charpart1, "%.2x", randomStore);
randomStore = rand() % 65535;
sprintf(charpart3, "%.4x", randomStore);
//Check if top level dir exists, create if not
strcat(path, "fastdirs/");
strcat(path, charpart1);
DIR *pdir=opendir(path);
//If the dir does not exist create it with read/write/search permissions for owner
// and group, and with read/search permissions for others
if(!pdir)
mkdir(path, S_IRWXU | S_IRWXG | S_IROTH | S_IXOTH);
//Check if 3rd level dir exists, create if not
strcat(path, "/");
strcat(path, charpart3);
DIR *pdir3=opendir(path);
if(!pdir3)
mkdir(path, S_IRWXU | S_IRWXG | S_IROTH | S_IXOTH);
strcat(path, "/");
strcat(path, charpart3);
strcat(path, ".txt");
//Write the file if it does not already exist
checkforfile.open(path, fstream::in);
if (checkforfile.is_open() != true)
{
fsWriteFiles.open(path, ios::app);
if(!fsWriteFiles.is_open())
{
cout << "Fail at point: " << dircount << "\n" << endl;
return 1;
}
fsWriteFiles << "test";
fsWriteFiles.flush();
fsWriteFiles.close();
dircount ++; //increment the file counter
}
else
{
cout << "ex";
checkforfile.close();
}
}
}
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
2270 次 |
| 最近记录: |