Wes*_*ter 4 formal-verification verilog properties system-verilog system-verilog-assertions
我有两个打包的信号数组,我需要为该属性创建一个属性和相关的断言,证明这两个数组在某些条件下是相同的.我正式验证并且该工具无法在单个属性中证明两个完整数组,因此我需要将其拆分为单个元素.那么有没有办法可以使用循环为数组的每个元素生成属性?目前,我的代码非常冗长,难以导航.
我的代码目前看起来像这样:
...
property bb_3_4_p;
@(posedge clk)
bb_seq
|=>
bb_exp [3][4] == bb_rtl [3][4] ;
endproperty
property bb_3_5_p;
@(posedge clk)
bb_seq
|=>
bb_exp [3][5] == bb_rtl [3][5] ;
endproperty
property bb_3_6_p;
@(posedge clk)
bb_seq
|=>
bb_exp [3][6] == bb_rtl [3][6] ;
endproperty
...
...
assert_bb_3_4: assert property (bb_3_4_p);
assert_bb_3_5: assert property (bb_3_5_p);
assert_bb_3_6: assert property (bb_3_6_p);
...
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这就像我希望我的代码看起来像:
for (int i = 0; i < 8; i++)
for (int j = 0; j < 8; j++)
begin
property bb_[i]_[j]_p;
@(posedge clk)
bb_seq
|=>
bb_exp [i][j] == bb_rtl [i][j] ;
endproperty
assert_bb_[i]_[j]: assert property (bb_[i]_[j]_p);
end
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小智 13
您可以尝试使用端口声明属性,以便可以将其重用于多个断言.然后使用generate循环声明你的断言.
module
...
property prop1(signal1,signal2);
@(posedge clk)
bb_seq
|=>
signal1 == signal2 ;
endproperty
...
generate
for (genvar i = 0; i < 8; i++)
for (genvar j = 0; j < 8; j++)
begin : assert_array
assert property (prop1(bb_exp[i][j],bb_rtl[i][j]));
end
endgenerate
...
endmodule
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您还可以在断言中内联属性:
module
...
generate
for (genvar i = 0; i < 8; i++)
for (genvar j = 0; j < 8; j++)
begin : assert_array
assert property (@(posedge clk) bb_seq |=> bb_exp[i][j] == bb_rtl[i][j]);
end
endgenerate
...
endmodule
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