我们说t1是:
t1 <- array(1:20, dim=c(10,10))
      [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
 [1,]    1   11    1   11    1   11    1   11    1    11
 [2,]    2   12    2   12    2   12    2   12    2    12
 [3,]    3   13    3   13    3   13    3   13    3    13
 [4,]    4   14    4   14    4   14    4   14    4    14
 [5,]    5   15    5   15    5   15    5   15    5    15
 [6,]    6   16    6   16    6   16    6   16    6    16
 [7,]    7   17    7   17    7   17    7   17    7    17
 [8,]    8   18    8   18    8   18    8   18    8    18
 [9,]    9   19    9   19    9   19    9   19    9    19
[10,]   10   20   10   20   10   20   10   20   10    20
我想从这个矩阵中删除第4-6行和第7-9行.
我知道如何逐个删除它
t2 <- t1[,-7]
t3 <- t2[,-8]
t4 <- t3[,-9]
t5 <- t4[-4,]
t6 <- t5[-5,]
t7 <- t6[-6,]
但是,我认为这是最愚蠢的做法.您能介意一些更聪明的方法吗?
tca*_*h21 60
你可以做:
t1<- t1[-4:-6,-7:-9]
您可以使用
t1<- t1[-4:-6,-7:-9]  
要么
t1 <- t1[-(4:6), -(7:9)]
要么
t1 <- t1[-c(4, 5, 6), -c(7, 8, 9)]
您可以传递vectors选择rows/columns要删除.如果您尝试删除连续的行/列,前两个方法很有用.如果您尝试删除离散, 则第三种方法很有用rows/columns.
> t1 <- array(1:20, dim=c(10,10));
> t1[-c(1, 4, 6, 7, 9), -c(2, 3, 8, 9)]
     [,1] [,2] [,3] [,4] [,5] [,6]
[1,]    2   12    2   12    2   12
[2,]    3   13    3   13    3   13
[3,]    5   15    5   15    5   15
[4,]    8   18    8   18    8   18
[5,]   10   20   10   20   10   20