Ale*_*huk 39 r data-visualization large-data
我制作了一个300万分的情节并将其保存为PNG.花了几个小时,我想避免重新绘制所有要点.

如何生成以PNG为背景的新图?
bil*_*080 80
试试这个:
library(png)
#Replace the directory and file information with your info
ima <- readPNG("C:\\Documents and Settings\\Bill\\Data\\R\\Data\\Images\\sun.png")
#Set up the plot area
plot(1:2, type='n', main="Plotting Over an Image", xlab="x", ylab="y")
#Get the plot information so the image will fill the plot box, and draw it
lim <- par()
rasterImage(ima, lim$usr[1], lim$usr[3], lim$usr[2], lim$usr[4])
grid()
lines(c(1, 1.2, 1.4, 1.6, 1.8, 2.0), c(1, 1.3, 1.7, 1.6, 1.7, 1.0), type="b", lwd=5, col="white")
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下面是情节.

cbe*_*ica 17
虽然@ bill_080的答案直接回答了你的问题,这真的是你想要的吗?如果要绘制到此图上,则必须仔细对齐坐标系.参见例如休斯顿犯罪地图如何使用ggplot2完成此操作.
对于你的问题,在我看来,可能有一个更容易的解决方案:binning,即停止2d直方图.
> df <- data.frame (x = rnorm (1e6), y = rnorm (1e6))
> system.time (plot (df))
User System verstrichen
54.468 0.044 54.658
> library (hexbin)
> system.time (binned <- hexbin (df, xbins=200))
User System verstrichen
0.252 0.012 0.266
> system.time (plot (binned))
User System verstrichen
0.704 0.040 0.784
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hexbin直接使用lattice和ggplot2,但是bin的中心坐标是binned@xcm和binned@ycm,所以你也可以在基本图形中绘制结果.拥有大量垃圾箱,您可以获得原始情节的快速版本:
> system.time (plot (binned@xcm, binned@ycm, pch = 20, cex=0.4))
User System verstrichen
0.780 0.004 0.786
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但你可以很容易地得到编码密度的颜色:
> plot (binned@xcm, binned@ycm, pch = 20, cex=0.4, col = as.character (col))
> col <- cut (binned@count, 20)
> levels (col) <- grey.colors (20, start=0.9, end = 0)
> plot (binned@xcm, binned@ycm, pch = 20, cex=0.4, col = as.character (col))
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