pro*_*ock 14 jquery jquery-datatables
看起来应该很容易但......
有谁知道如何从过滤后的dataTable返回当前行?该oTable.fnGetNodes()
方法返回所有行,我只想要过滤(可见,但包括分页)
// filter on division
var oTable = $('#summary-table').dataTable();
oTable.fnFilter(division_text, 2, true);
// Get the nodes from the table
var nNodes = oTable.fnGetNodes(); // <-- still retrieves original list of rows
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我检查过:从Datatables中检索可见数据,但没有太多帮助.
Joe*_*vin 16
实现此目的的最简单方法实际上是内置于DataTables API:
_('tr', {"filter": "applied"})
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用于函数:
function get_filtered_datatable() {
var filteredrows = $("#mydatatable").dataTable()._('tr', {"filter": "applied"});
for ( var i = 0; i < filteredrows.length; i++ ) {
debug.console(filteredrows[i]);
};
}
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小智 14
从Datatables 1.10开始,有一种内置方法可以在搜索后获取已过滤或未过滤的行.
var table = $('#example').DataTable();
table.rows( {search:'applied'} ).nodes();
table.rows( {search:'removed'} ).nodes();
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还有其他选项可以只获取当前页面或所有页面以及订单.更多细节在这里:http: //datatables.net/reference/type/selector-modifier
找出答案,如果有人需要这个:
首先,使用此数据表扩展来获取所有隐藏行:
$.fn.dataTableExt.oApi.fnGetHiddenTrNodes = function (oSettings, arg1, arg2) {
/* Note the use of a DataTables 'private' function thought the 'oApi' object */
var anNodes = this.oApi._fnGetTrNodes(oSettings);
var anDisplay = $('tbody tr', oSettings.nTable);
/* Remove nodes which are being displayed */
for (var i = 0; i < anDisplay.length; i++) {
var iIndex = jQuery.inArray(anDisplay[i], anNodes);
if (iIndex != -1) {
anNodes.splice(iIndex, 1);
}
}
/* Fire back the array to the caller */
return anNodes;
}
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然后过滤掉隐藏节点,只得到可见节点:
var rows = oTable.fnGetNodes(); // get all nodes
var rows_hidden = oTable.fnGetHiddenTrNodes(); // get all hidden nodes
var result = [], found;
// remove hidden nodes from all nodes
for (var i = 0; i < rows.length; i++) {
found = false;
for (var j = 0; j < rows_hidden.length; j++) {
if (rows[i] == rows_hidden[j]) {
found = true;
break;
}
}
if (!found) {
result.push(rows[i]);
}
}
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