Mat*_*one 11 javascript node.js gruntjs
我的grunt.js有一个典型的缩小任务:
min: {
dist: {
src: ['dist/precook.js'],
dest: 'dist/precook.min.js'
}
}
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拥有多个dest文件的最简单方法是什么?我想缩小成:
该内置分钟的任务似乎并不支持多目的地,所以我认为这可以通过一个简单的"复制"任务来实现.有人可以指点我正确的方向吗?
我会使用grunt-contrib-copy插件:
使用npm安装:
npm install grunt-contrib-copy
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修改grunt.js
(添加复制任务定义和加载复制插件):
...
copy: {
dist: {
files: {
'example/js/vendor/': 'dist/precook.min.js'
}
}
}
...
grunt.loadNpmTasks('grunt-contrib-copy');
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可以选择注册copy
到grunt的默认任务.
这里增加的美妙之处在于您现在也可以执行所有其他复制任务.甚至支持模式,例如复制所有缩小的文件('dist/*.min.js'
).
concat: {
css: {
src: ['UI.controls/assets/css/*.css'],
dest: 'UI.controls/assets/css/min/production.css'
},
js: {
src: ['UI.controls/assets/js/*.js'],
dest: 'UI.controls/assets/js/min/production.js'
},
js2: {
src: ['UI.core/assets/js/*.js'],
dest: 'UI.core/assets/js/min/production.js'
}
},
cssmin: {
css: {
src: 'UI.controls/assets/css/min/production.css',
dest: 'UI.controls/assets/css/min/production.min.css'
}
},
uglify: {
js: {
src: 'UI.controls/assets/js/min/production.js',
dest: 'UI.controls/assets/js/min/production.min.js'
},
js2: {
src: 'UI.core/assets/js/min/production.js',
dest: 'UI.core/assets/js/min/production.min.js'
}
},
watch: {
css: {
files: ['UI.controls/assets/css/*.css'],
tasks: ['concat:css', 'cssmin:css']
},
js: {
files: ['UI.controls/assets/js/*.js'],
tasks: ['concat:js', 'uglify:js']
},
js2: {
files: ['UI.core/assets/js/*.js'],
tasks: ['concat:js', 'uglify:js']
}
}
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