Mysql,根据日期选择行

Question

我想做的事情:

选择date = 2012-10-14的行,然后显示该行之后的4行.所以从这个列表中

2012-10-12 column #2
2012-10-13 column #2
2012-10-14 was very sunny.
2012-10-15 rained all day.
2012-10-16 whatever.
2012-10-17 column #2
2012-10-18 column #2
2012-10-19 rained all day.
2012-10-20 whatever.
2012-10-21 column #2
2012-10-22 column #2

它会返回这个:

2012-10-14 was very sunny.
2012-10-15 rained all day.
2012-10-16 whatever.
2012-10-17 column #2
2012-10-18 column #2

感谢帮助.

PS:在数据库中周末没有数据,所以有些日期会丢失.

Answer 1

SELECT * FROM my_table WHERE date >= '2012-10-14' ORDER BY date LIMIT 5

在sqlfiddle上看到它.