Hou*_*man 59 sql conditional count
如果我有这样一张桌子:
jobId, jobName, Priority
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其中,优先级可以是1到5之间的整数.
由于我需要此查询来生成报表上的图表,因此我需要显示jobid,jobname和名为Priority1,Priority2,Priority3,Priority4的5个字段.Priority5.
Priority1应计算优先级字段值为1的行数.
Priority2应计算优先级字段值为2的行数.
Priority3应计算优先级字段值为3的行数.
等等
我怎么能以快速和高效的方式做到这一点?
非常感谢,Kave
Dav*_*ick 110
我想你可能会追随
select
jobID, JobName,
sum(case when Priority = 1 then 1 else 0 end) as priority1,
sum(case when Priority = 2 then 1 else 0 end) as priority2,
sum(case when Priority = 3 then 1 else 0 end) as priority3,
sum(case when Priority = 4 then 1 else 0 end) as priority4,
sum(case when Priority = 5 then 1 else 0 end) as priority5
from
Jobs
group by
jobID, JobName
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但是我不确定你是否需要在结果中使用jobID和JobName,如果这样删除它们并删除组,
小智 72
使用COUNT而不是SUM将删除对ELSE语句的要求:
SELECT jobId, jobName,
COUNT(CASE WHEN Priority=1 THEN 1 END) AS Priority1,
COUNT(CASE WHEN Priority=2 THEN 1 END) AS Priority2,
COUNT(CASE WHEN Priority=3 THEN 1 END) AS Priority3,
COUNT(CASE WHEN Priority=4 THEN 1 END) AS Priority4,
COUNT(CASE WHEN Priority=5 THEN 1 END) AS Priority5
FROM TableName
GROUP BY jobId, jobName
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使用 ANSI SQL-92 CASE 语句,您可以执行以下操作(派生表加大小写):
SELECT jobId, jobName, SUM(Priority1)
AS Priority1, SUM(Priority2) AS
Priority2, SUM(Priority3) AS
Priority3, SUM(Priority4) AS
Priority4, SUM(Priority5) AS
Priority5 FROM (
SELECT jobId, jobName,
CASE WHEN Priority = 1 THEN 1 ELSE 0 END AS Priority1,
CASE WHEN Priority = 2 THEN 1 ELSE 0 END AS Priority2,
CASE WHEN Priority = 3 THEN 1 ELSE 0 END AS Priority3,
CASE WHEN Priority = 4 THEN 1 ELSE 0 END AS Priority4,
CASE WHEN Priority = 5 THEN 1 ELSE 0 END AS Priority5
FROM TableName
)
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IIF 不是标准的SQL构造,但是如果数据库支持,则可以实现更优雅的语句,产生相同的结果:
SELECT JobId, JobName,
COUNT(IIF (Priority=1, 1, NULL)) AS Priority1,
COUNT(IIF (Priority=2, 1, NULL)) AS Priority2,
COUNT(IIF (Priority=3, 1, NULL)) AS Priority3,
COUNT(IIF (Priority=4, 1, NULL)) AS Priority4,
COUNT(IIF (Priority=5, 1, NULL)) AS Priority5
FROM TableName
GROUP BY JobId, JobName
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