我正试图在android中创建一个新的来电屏幕,
当我接到一个来电我的应用程序启动 - 但立即崩溃,默认来电屏幕即将到来.
我究竟做错了什么?
我的代码:
AndroidManifest.xml:
<?xml version="1.0" encoding="utf-8" ?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.example.myfirstapp"
android:versionCode="7"
android:versionName="7">
<uses-sdk android:minSdkVersion="7" android:targetSdkVersion="10"></uses-sdk>
<uses-permission android:name="android.permission.READ_PHONE_STATE"/>
<uses-permission android:name="android.permission.MODIFY_PHONE_STATE"/>
<uses-permission android:name="android.permission.CALL_PHONE" />
<application android:label="@string/app_name" android:icon="@drawable/ic_launcher">
<receiver android:name=".MyPhoneBroadcastReceiver" android:enabled="true">
<intent-filter android:priority="99999">
<action android:name="android.intent.action.PHONE_STATE" />
</intent-filter>
</receiver>
<activity
android:name=".Call" >
</activity>
</application>
</manifest>
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MyPhoneBroadcastReceiver.java:
package com.example.myfirstapp;
import android.app.Activity;
import android.content.Context;
import android.content.Intent;
public class MyPhoneBroadcastReceiver extends Activity{
public void onReceive(final Context context, Intent intent) {
Intent main_intent = new Intent(this, Call.class);
context.startActivity(main_intent);
}
}
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Call.java:
package com.example.myfirstapp;
import android.app.Activity;
import android.os.Bundle;
public class Call extends Activity{
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
}
}
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日志是:
10-14 20:59:51.056: E/AndroidRuntime(1826): FATAL EXCEPTION: main
10-14 20:59:51.056: E/AndroidRuntime(1826):
java.lang.RuntimeException: Unable to instantiate receiver
com.example.myfirstapp.MyPhoneBroadcastReceiver:
java.lang.ClassCastException:
com.example.myfirstapp.MyPhoneBroadcastReceiver cannot be cast to
android.content.BroadcastReceiver 10-14 20:59:51.056:
E/AndroidRuntime(1826): at
android.app.ActivityThread.handleReceiver(ActivityThread.java:2210)
10-14 20:59:51.056: E/AndroidRuntime(1826): at
android.app.ActivityThread.access$1500(ActivityThread.java:130) 10-14
20:59:51.056: E/AndroidRuntime(1826): at
android.app.ActivityThread$H.handleMessage(ActivityThread.java:1271)
10-14 20:59:51.056: E/AndroidRuntime(1826): at
android.os.Handler.dispatchMessage(Handler.java:99) 10-14
20:59:51.056: E/AndroidRuntime(1826): at
android.os.Looper.loop(Looper.java:137) 10-14 20:59:51.056:
E/AndroidRuntime(1826): at
android.app.ActivityThread.main(ActivityThread.java:4745) 10-14
20:59:51.056: E/AndroidRuntime(1826): at
java.lang.reflect.Method.invokeNative(Native Method) 10-14
20:59:51.056: E/AndroidRuntime(1826): at
java.lang.reflect.Method.invoke(Method.java:511) 10-14 20:59:51.056:
E/AndroidRuntime(1826): at
com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:786)
10-14 20:59:51.056: E/AndroidRuntime(1826): at
com.android.internal.os.ZygoteInit.main(ZygoteInit.java:553) 10-14
20:59:51.056: E/AndroidRuntime(1826): at
dalvik.system.NativeStart.main(Native Method) 10-14 20:59:51.056:
E/AndroidRuntime(1826): Caused by: java.lang.ClassCastException:
com.example.myfirstapp.MyPhoneBroadcastReceiver cannot be cast to
android.content.BroadcastReceiver 10-14 20:59:51.056:
E/AndroidRuntime(1826): at
android.app.ActivityThread.handleReceiver(ActivityThread.java:2205)
10-14 20:59:51.056: E/AndroidRuntime(1826): ... 10 more
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好的,为了使我的新页面位于前面,我需要让它休眠一段时间......所以新代码将是:
public class MyPhoneBroadcastReceiver extends BroadcastReceiver{
public void onReceive(final Context context, Intent intent) {
Thread pageTimer = new Thread(){
public void run(){
try{
sleep(1000);
} catch (InterruptedException e){
e.printStackTrace();
} finally {
Intent i = new Intent();
i.setClass(context, Call.class);
i.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
context.startActivity(i);
}
}
};
pageTimer.start();
}
}
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但是——原来的来电程序还在后台运行……
有什么方法可以替换它,而不是在它上面打开新的应用程序?
谢谢!
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