我试图在本地运行Node.js脚本,它给我这个错误消息:
Run Code Online (Sandbox Code Playgroud)======================================================================================== = Please ensure that you set the default safe variable to one of the = = allowed values of [true | false | {j:true} | {w:n, wtimeout:n} | {fsync:true}] = = the default value is false which means the driver receives does not = = return the information of the success/error of the insert/update/remove = = = = ex: new Db(new Server('localhost', 27017), {safe:false}) = = = = http://www.mongodb.org/display/DOCS/getLastError+Command = = = = The default of false will change to true in the near future = = = = This message will disappear when the default safe is set on the driver Db = ========================================================================================
这是我的变量:
var express = require('express');
var mongodb = require('mongodb');
var GridStore = require('mongodb').GridStore;
var Db = require('mongodb').Db;
var Server = require('mongodb').Server;
var db = new Db(Config.dbName, new Server("127.0.0.1", 27017, {}), {});
var HttpGet = require('./httpGet').HttpGet;
var URL = require('url');
var dbClient = null; // this is initialized when db is opened
var app = module.exports = express();
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在我的实时服务器上运行相同的脚本.它只会在我在本地运行时抱怨.
我发现在github上讨论了同样的问题,但没有找到解决方案. https://github.com/kissjs/node-mongoskin/issues/77
谁知道什么可能导致这个问题?
提前致谢 :)
Joh*_*yHK 22
以下适用于我使用1.1.11 mongo驱动程序:
var db = new Db(Config.dbName, new Server("127.0.0.1", 27017, {}), {safe: true});
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如果没有{safe: true}参数,我会收到您在问题中显示的相同警告.
这个警告是司机的最新补充; 你可能在你的服务器上使用旧版本的驱动程序,这就是你没有在那里看到警告的原因.
我通过将strict模式设置为false 来使其工作.
var db = new Db(config.dbName, new Server("127.0.0.1", 27017, {}), {safe: false, strict: false});
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