错误:返回void,返回关键字后面不能跟对象表达式

Zay*_*ayn 1 c# return

    private void QuestionAnswer_Load(object sender, EventArgs e)
    {

        txtQuestion.Enabled = false;
        txtQuestion.BackColor = Color.White;
        grpMultipleChoice.Enabled = false;
        grpSingleChoice.Enabled = false;

        btnCheckAnswer.Enabled = false;
        btnNext.Enabled = false;
        btnQuit.Enabled = false;

        //force student to enter registration details
        if (txtStudentName.Text == "" && txtStudentNumber.Text == "" && txtModuleNumber.Text == "")
        {
            btnStart.Enabled = false;
            MessageBox.Show("You must enter your registration details at the upper right corner");
        }

        //declare a list
        lstNumbers = new ArrayList();

        //create a random number generator
        Random rndNumber = new Random();

        //generate 70 random numbers
        //int number = (int)(rndNumber.NextDouble() * 69) + 1;

        //lstNumbers.Add(number);
        ///use this counter to loop whenever a number is generated
        int count = 0;
        int maximumNumber = 69;

        ///disable answer button 
        btnCheckAnswer.Enabled = false;
        do
        {

            int number = (int)(rndNumber.NextDouble() * maximumNumber) + 1;
            lstNumbers.Add(number);
            if (!lstNumbers.Contains(number))
            {
                lstNumbers.Add(number);
            }
            count++;

        } while (count <= 15 * 70);//
        btnCheckAnswer_Click(sender, e);
        return lstNumbers;//returns once list is built
     }
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说明:我创建了一个arraylist,允许我在1-70之间随机生成,但注意到我的数字有点重复.为了防止这种情况,我注意到我收到以下错误消息:

错误1由于'wwTestAppV1.GenKnow.QuestionAnswer_Load(object,System.EventArgs)' 返回void,因此返回关键字后面的对象表达式不能出现

我已尽力解决这个问题.当我删除此语句但显示重复值时程序运行良好.能否请你帮忙?

Kac*_*che 8

您的方法签名是:

private void QuestionAnswer_Load(object sender, EventArgs e)
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返回类型void意味着您不能/不打算返回任何内容.但是,在底部,您有:

return lstNumbers;//returns once list is built
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你回来了!编译器抱怨你告诉它有冲突的指令.将返回类型更改为ArrayList或不返回任何内容.

话虽如此,可以对代码进行一些改进,使其更具可读性,这也将帮助您解决问题.考虑将您的代码提交到https://codereview.stackexchange.com/.