如何将智能标记添加到我的.NET组件？

Question

请看下面的图片,它显示了DataGridView的智能标记.

DataGridView智能标签http://img199.imageshack.us/img199/5871/post517531249536112.jpg

现在我正在创建一个新组件,我希望它支持在智能标记中显示一些属性.如何将属性添加到智能标记？

Answer 1

我使用了http://msdn.microsoft.com/en-us/library/default.aspx?q=smart+tag+windows+forms+designer.

因此,我发现了演练:将智能标记添加到Windows窗体组件.

执行相同搜索的任何人都会找到相同的文章.

更新:该链接不再有效.我刚刚尝试搜索"智能标记窗体表单设计器",并发现"演练:将智能标记添加到Windows窗体组件"作为第一个搜索命中.Google中的相同搜索显示"如何:将智能标记附加到Windows窗体组件"作为第一个匹配,但显示与第二次匹配相同的演练.

Answer 2

您可以使用以下代码查看自定义控件中的示例标记。

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您可以从 www.windowsclient.com 获取有关该内容的视频。

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using System;\nusing System.Collections.Generic;\nusing System.ComponentModel;\nusing System.Drawing;\nusing System.Data;\nusing System.Text;\nusing System.Windows.Forms;\nusing System.ComponentModel.Design;\nnamespace MakeSmartTag\n{\n    public enum Languages\n    {\n        English,\n        Arabic,\n        Japanese\n    }\n\n    [Designer(typeof(UserControlDesigner))]\n    public partial class UserControl2 : UserControl\n    {\n        public UserControl2()\n        {\n            InitializeComponent();\n        }\n\n        private Languages _language;\n\n        public Languages Language\n        {\n            get { return _language; }\n            set\n            {\n                switch (value)\n                {\n                    case Languages.Arabic:\n                        {\n                            label1.Text = "\xd9\x85\xd8\xb1\xd8\xad\xd8\xa8\xd8\xa7\xd9\x8b";\n                            _language = value;\n                        }\n                        break;\n                    case Languages.English:\n                        {\n                            label1.Text = "Hello";\n                            _language = value;\n                        }\n                        break;\n                    case Languages.Japanese:\n                        {\n                            label1.Text = "Conechoa";\n                            _language = value;\n                        }\n                        break;\n                }\n            }\n        }\n    }\n\n    public class UserControlDesigner : System.Windows.Forms.Design.ControlDesigner\n    {\n        private DesignerActionListCollection lists;\n        public override DesignerActionListCollection ActionLists\n        {\n            get\n            {\n                if (lists == null)\n                {\n\n                    lists = new DesignerActionListCollection();\n                    lists.Add(new UserControlActioonList(this.Component));\n                }\n                return lists;\n            }\n        }\n    }\n\n    public class UserControlActioonList : DesignerActionList\n    {\n        private UserControl2 myUserControl;\n        private DesignerActionUIService designerActionSvc = null;\n\n        public UserControlActioonList(IComponent component)\n            : base(component)\n        {\n            this.myUserControl = (UserControl2)component;\n\n            this.designerActionSvc =\n              (DesignerActionUIService)GetService(typeof(DesignerActionUIService));\n        }\n\n        private PropertyDescriptor GetPropertyByName(string propName)\n        {\n            PropertyDescriptor prop = default(PropertyDescriptor);\n            prop = TypeDescriptor.GetProperties(myUserControl)[propName];\n            if (prop == null)\n            {\n                throw new ArgumentException("Invalid Property", propName);\n            }\n            else\n            {\n                return prop;\n            }\n        }\n\n        public override System.ComponentModel.Design.DesignerActionItemCollection GetSortedActionItems()\n        {\n            DesignerActionItemCollection item = new DesignerActionItemCollection();\n            item.Add(new DesignerActionHeaderItem(\n                       "\xd8\xa7\xd9\x84\xd9\x85\xd8\xb8\xd9\x87\xd8\xb1"));\n            item.Add(new DesignerActionPropertyItem(\n                       "BackColor", "\xd9\x84\xd9\x88\xd9\x86 \xd8\xa7\xd9\x84\xd8\xae\xd9\x84\xd9\x81\xd9\x8a\xd8\xa9", "Appearance", "Set background Color of the control"));\n            item.Add(new DesignerActionHeaderItem("\xd8\xaa\xd8\xad\xd8\xaf\xd9\x8a\xd8\xaf \xd8\xa7\xd9\x84\xd9\x84\xd8\xba\xd8\xa9"));\n            item.Add(new DesignerActionPropertyItem(\n                       "Language", "\xd8\xa7\xd9\x84\xd9\x84\xd8\xba\xd8\xa9", "Functions", "Set the language of the control"));\n            return item;\n        }\n\n        public Color BackColor\n        {\n            get { return this.myUserControl.BackColor; }\n            set { GetPropertyByName("BackColor").SetValue(myUserControl, value); }\n        }\n\n        public Languages Language\n        {\n            get { return this.myUserControl.Language; }\n            set { GetPropertyByName("Language").SetValue(myUserControl, value); }\n        }\n    }\n}\n

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