在Mysql查询中划分

Question

我有2个不同的查询,它将返回值:1502.00和6

SELECT replace(CURRENT_VALUE,'$','') curVal
FROM form_attributes_values
WHERE TEST_ID=2
AND ATTRIBUTE_ID = (
    SELECT ATTRIBUTE_ID
    FROM form_attributes
    WHERE FORM_ID=6
    AND FORM_FIELD_NAME='REGRINDABLECUTTERCOST'
)

和

SELECT replace(CURRENT_VALUE,'$','') curVal
FROM form_attributes_values
WHERE TEST_ID=2
AND ATTRIBUTE_ID = (
    SELECT ATTRIBUTE_ID
    FROM form_attributes
    WHERE FORM_ID=6
    AND FORM_FIELD_NAME='REGRINDSPOSSIBLE'
)

我试图执行分区query1/query2(1502.00/6),它应该返回值 250.333333

但我得到的价值就像 0.16666666666666

以下是尝试过的类型:类型1:

select (a.curVal / b.curVal) as final_count
from (
    SELECT replace(CURRENT_VALUE,'$','') curVal
    FROM form_attributes_values
    WHERE TEST_ID=2 AND ATTRIBUTE_ID = (
        SELECT ATTRIBUTE_ID
        FROM form_attributes
        WHERE FORM_ID=6
        AND FORM_FIELD_NAME='REGRINDABLECUTTERCOST'
    )
) a,
(
    SELECT replace(CURRENT_VALUE,'$','') curVal
    FROM form_attributes_values
    WHERE TEST_ID=2
    AND ATTRIBUTE_ID = (
        SELECT ATTRIBUTE_ID
        FROM form_attributes
        WHERE FORM_ID=6
        AND FORM_FIELD_NAME='REGRINDSPOSSIBLE'
    )
) b;

类型2:

SELECT replace(CURRENT_VALUE,'$','') / (
    SELECT replace(CURRENT_VALUE,'$','') curVal
    FROM form_attributes_values
    WHERE TEST_ID=2
    AND ATTRIBUTE_ID = (
        SELECT ATTRIBUTE_ID
        FROM form_attributes
        WHERE FORM_ID=6
        AND FORM_FIELD_NAME='REGRINDSPOSSIBLE'
    )
) curVal
FROM form_attributes_values
WHERE TEST_ID=2
AND ATTRIBUTE_ID = (
    SELECT ATTRIBUTE_ID
    FROM form_attributes
    WHERE FORM_ID=6
    AND FORM_FIELD_NAME='REGRINDABLECUTTERCOST'
)

两种类型的返回0.166666666666667我错过了什么......？

Answer 1

select sum(a.curVal) / sum(b.curVal) as final_count from 
(SELECT replace(CURRENT_VALUE,'$','') curVal FROM form_attributes_values WHERE TEST_ID=2     AND ATTRIBUTE_ID = (SELECT ATTRIBUTE_ID FROM form_attributes WHERE FORM_ID=6     AND FORM_FIELD_NAME='REGRINDABLECUTTERCOST')) a,
(SELECT replace(CURRENT_VALUE,'$','') curVal FROM form_attributes_values WHERE TEST_ID=2 AND ATTRIBUTE_ID = (SELECT ATTRIBUTE_ID FROM form_attributes WHERE FORM_ID=6 AND FORM_FIELD_NAME='REGRINDSPOSSIBLE')) b;

它尚未经过测试，但使用 SUM 应该会更好。

希望这可以帮助