拆分列表中的项目

Question

我该如何转换以下列表

['1','2','A,B,C,D','7','8']

成

['1','2','A','B','C','D','7','8']

以最pythonic的方式？

我有非常unpythonic代码创建嵌套列表,然后flatterens:

sum ( [ word.split(',') for word in words ], [] )

Answer 1

result = [item for word in words for item in word.split(',')]