我有这个为Access DB编写的查询.
queryText = "SELECT Technicians.ID, firstName, lastName, Technicians.[Zone],
COUNT(technicianAssignedId) AS JobsDone,
MAX(Faults.timeCompleted) AS LastJobTime,
MIN(Technicians.[Zone] - & faultZone &) AS Distance ' MIN has no use
FROM Technicians LEFT OUTER JOIN Faults ON
Technicians.ID = Faults.technicianAssignedID
WHERE Specialization = '" & specialization & "'
`AND Availability = 'available'
GROUP BY Technicians.ID, firstName, lastName, Availability,` Technicians.[Zone], Specialization
ORDER BY 7 DESC"
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我有这个获得绝对价值
SELECT CASE
WHEN value < 0 THEN value * -1
ELSE number *1 END
AS VALUE
FROM DB;
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现在,带有Distance别名的列可能最终为负数,我需要使用(*-1)作为正数,但我无法弄清楚如何将它们组合在一起.
谢谢你的帮助
尝试
ABS(Technicians.[Zone] - & faultZone &) AS Distance
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参见ABS doc