计算目录php中的文件数量

Question

我正在开发一个稍微新的项目.我想知道如何制作它,以便计算某个目录中有多少文件.

<div id="header">
<?php 
    $dir = opendir('uploads/'); # This is the directory it will count from
    $i = 0; # Integer starts at 0 before counting

    # While false is not equal to the filedirectory
    while (false !== ($file = readdir($dir))) { 
        if (!in_array($file, array('.', '..') and !is_dir($file)) $i++;
    }

    echo "There were $i files"; # Prints out how many were in the directory
?>
</div>

这是我到目前为止(从搜索).但它出现不正常？我添加了一些注释,所以随意删除它们,它们只是让我尽可能地理解它.

如果您需要更多信息或觉得我没有详细描述,请随时说明.

Answer 1

您可以简单地执行以下操作:

$fi = new FilesystemIterator(__DIR__, FilesystemIterator::SKIP_DOTS);
printf("There were %d Files", iterator_count($fi));

Answer 2

您可以像这样获取文件计数:

$directory = "/path/to/dir/";
$filecount = 0;
$files = glob($directory . "*");
if ($files){
 $filecount = count($files);
}
echo "There were $filecount files";

其中"*"是可以更改的特定文件类型,如果你想要一个像"*.jpg",或者你可以做多种文件类型是这样的:

glob($directory . "*.{jpg,png,gif}",GLOB_BRACE)

该GLOB_BRACE标志展开{a,b,c}以匹配'a','b'或'c'

Answer 3

你应该有 :

<div id="header">
<?php 
    // integer starts at 0 before counting
    $i = 0; 
    $dir = 'uploads/';
    if ($handle = opendir($dir)) {
        while (($file = readdir($handle)) !== false){
            if (!in_array($file, array('.', '..')) && !is_dir($dir.$file)) 
                $i++;
        }
    }
    // prints out how many were in the directory
    echo "There were $i files";
?>
</div>

Answer 4

试试这个.

// Directory
$directory = "/dir";

// Returns array of files
$files = scandir($directory);

// Count number of files and store them to variable..
$num_files = count($files)-2;

不计算'.' 和'..'.

Answer 5

既然我也需要这个,我很好奇哪个选择最快.

我发现-如果你想要的是一个文件计数-巴巴的解决方案是很多比别人快.我很惊讶.

自己试试吧:

<?php
define('MYDIR', '...');

foreach (array(1, 2, 3) as $i)
{
    $t = microtime(true);
    $count = run($i);
    echo "$i: $count (".(microtime(true) - $t)." s)\n";
}

function run ($n)
{
    $func = "countFiles$n";
    $x = 0;
    for ($f = 0; $f < 5000; $f++)
        $x = $func();
    return $x;
}

function countFiles1 ()
{
    $dir = opendir(MYDIR);
    $c = 0;
    while (($file = readdir($dir)) !== false)
        if (!in_array($file, array('.', '..')))
            $c++;
    closedir($dir);
    return $c;
}

function countFiles2 ()
{
    chdir(MYDIR);
    return count(glob("*"));
}

function countFiles3 () // Fastest method
{
    $f = new FilesystemIterator(MYDIR, FilesystemIterator::SKIP_DOTS);
    return iterator_count($f);
}
?>

测试运行:(显然,glob()不计算点文件)

1: 99 (0.4815571308136 s)
2: 98 (0.96104407310486 s)
3: 99 (0.26513481140137 s)

Answer 6

工作演示

<?php

$directory = "../images/team/harry/"; // dir location
if (glob($directory . "*.*") != false)
{
 $filecount = count(glob($directory . "*.*"));
 echo $filecount;
}
else
{
 echo 0;
}

?>

Answer 7

我认为最好的答案是：

$num = count(glob("/exact/path/to/files/" . "*"));
echo $num;

• 它不算数。和..
• 其一班轮
• 我为此感到骄傲

Answer 8

我用这个：

count(glob("yourdir/*",GLOB_BRACE))